Answer:
Step-by-step explanation:
Remark
The formula for this is
Heat = m * c * Δt
Givens
Heat = unknown
m = 200 grams
c = 4.184 Joules / grams oC
Δt = the change in temperature = 35.7 - 22.3 = 13.4
Solution
Heat = 200 * 4.184 * 13.4
Heat = 11213 Joules
Heat = 11.2 Kj
It's hard to get the correct number of sig digs because the 200 is not qualified in any way.
Part 2.
This can really puzzle you until you know that heat given up = the heat taken on. The heat taken on was 11.2 Kj. The Butane lighter must have given that heat on.
Heat of Combustion = Heat Given Up / Number grams burned.
Heat of Combustion = 11.2 Kj / 0.23 grams
Heat of Combustion = 48.8 Kj / gram
(-3x)⁴
Basically, just do this :
(-3x) × (-3x) × (-3x) × (-3x)
So now you have 9x² × 9x²
9 × 9 = 81
x² × x² = x⁴
So, your answer is 81x⁴
~Hope I helped!~
Answer:
x = 24
Step-by-step explanation:
I checked and made sure the answer was correct.
Hope this helps!
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<u>Answer</u>
12 units
<u>Explanation</u>
This can be solved using the properties of a circle.
DG and EG are secants f the circle.
DG×HG =EG×FG
(x+3+5)×5 = (x+6)×6
(x+8)5 = 6x + 36
5x +40 = 6x + 36
x = 4
DG = (x+3+5)
= 4 + 3 + 5
= 12 units
