Answer:
Yes, A KLP can be reflected across the line containing KP and then translated so that Pis mapped to M.
Step-by-step explanation:
The figure shows two congruent by HA theorem (they have congruent hypotenuses and a pair of congruent angles adjacent to the hypotenuses) triangles KLP and QNM.
A rigid transformation is a transformation which preserves lengths. Reflection, rotation and translation are rigit transformations.
If you reflect triangle KLP across the leg KP and translate it up so that point P coincides with point M , then the image of triangle KLP after these transformations will be triangle QNM.
Where is the pic of the angles to measure ? I would help
You
Answer:
The image is sideways.
But if your graph is like on the image, then the answer is: {y│-3 ≤ y ≤ 4}
Range is the set of y values
Least function value is -3 and greatest is 4
Travis got 43 dollars
Robin collected 35 percent more so we can model this with
Travis + (Travis x .35)
43 + 15.05 =58.05
Jessica colelcted 20 percent less so
Travis - (Travis x .20)
43 - 8.6 = 34.3
34.4 + 58.05 + 43 = 135.45
C is the closest
Answer: x=9
Step-by-step explanation:
The bottom triangle that has a 40° is an isosceles triangle, therefore the other angle at the bottom right is also 40°. This leaves the top angle to be 100°.
180=40+40+x
180=80+x
x=100
Now, to find ∠2, you can tell it is a supplementary angle. Therefore, the 2 angles add up to 180°
180-100=∠2
80°=∠2
The problem states that ∠2 is 9x-1. We know that ∠2 is 80°. We can solve for x.
80=9x-1
81=9x
x=9