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SIZIF [17.4K]
3 years ago
6

64, –48, 36, –27, ...

Mathematics
2 answers:
daser333 [38]3 years ago
5 0

Answer:

f(x + 1) = -(3/4)*f(x)

(second option)

Step-by-step explanation:

Here we have the sequence:

64, -48, 36, -27, ...

First, we can notice two things:

Each term has a different sign than the previous term, so the relation is something like:

f(x + 1) = -k*f(x)

Now to find the value of k, we can just replace some of the values (for example, the first and the second one)

-48 = -k*64

48/64 = k

3/4 = k

Now, if we use any pair of consecutive terms we should get the same value of k, now let's try to use the second and third terms to see if we get the same value of k:

36 = -k*(-48)

36 = k*48

36/48 = k

3/4 = k

We got the same value, so we can conclude that k = (3/4)

Then the relation that describes this sequence is:

f(x + 1) = -(3/4)*f(x)

Sergeu [11.5K]3 years ago
5 0

Answer:

a

Step-by-step explanation:

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Answer:

0.5981 = 59.81% probability that three or less of the selected adults have saved nothing for retirement

Step-by-step explanation:

For each adult, there are only two possible outcomes. Either they save nothing for retirement, or they save something. The probability of an adult saving nothing for retirement is independent of any other adult. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

20% of adults in the United States save nothing for retirement (CNBC website).

This means that p = 0.2

Suppose that sixteen adults in the United States are selected randomly.

This means that n = 16

What is the probability that three or less of the selected adults have saved nothing for retirement?

This is:

P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{16,0}.(0.2)^{0}.(0.8)^{16} = 0.0281

P(X = 1) = C_{16,1}.(0.2)^{1}.(0.8)^{15} = 0.1126

P(X = 2) = C_{16,2}.(0.2)^{2}.(0.8)^{14} = 0.2111

P(X = 3) = C_{16,3}.(0.2)^{3}.(0.8)^{13} = 0.2463

P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.0281 + 0.1126 + 0.2111 + 0.2463 = 0.5981

0.5981 = 59.81% probability that three or less of the selected adults have saved nothing for retirement

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