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BabaBlast [244]
3 years ago
7

Which of the following options will definitely balance the third scale?

Mathematics
1 answer:
mel-nik [20]3 years ago
6 0

Answer:

I'd say b... But I'm not very confident about it.. Let me know if it's right.

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PLEASE HELP!!! I NEED THIS FAST!!
Maksim231197 [3]

Answer:

a. In a one-to-many relation, at least one (input) value maps to (more than one) (output) value. This means a one-to-many relation (cannot) be a function,

Step-by-step explanation:

7 0
3 years ago
Sophie has 5 pieces of string that are 4 yards each. She uses 3 pieces that are each 3 feet long. How much string does Sophie ha
stich3 [128]

Alright, lets get started.

Sophie has 5 pieces of string that are 4 yards each.

1 yards = 3 feet,

So, 4 yards = 4 * 3 =12 feet

Total number of string she has = 5 piece

So, total length she has = 5*12 = 60 feet

It means she had 60 feet string in starting.

Now, She uses 3 pieces that are each 3 feet long, means

She uses = 3*3 = 9 feet

So, remaining string length will be = 60 - 9 = 51 feet

Means 51 feet string does Sophie have. : Answer

Hope it will help :)


5 0
3 years ago
Read 2 more answers
Can someone help me figure this out: Factor 12y^2-27? I keep getting the steps confused.
alukav5142 [94]
Factor out the gcf first.

3(4y^2-9)

The binomial inside is a perfect square so keep factoring.

3(2y+3)(2y-3)

The pair of binomials cannot be further factored so stop there.
8 0
3 years ago
does the following system of equations have a solution if so find it. 2x+y+z= 4 x-y+3z= -2 -x+y+z= -2
saul85 [17]
I'd suggest using "elimination by addition and subtraction" here, altho' there are other approaches (such as matrices, substitution, etc.).

Note that if you add the 3rd equation to the second, the x terms cancel out, and you are left with the system

 - y + 3z = -2
   y  + z  =  -2
-----------------
         4z = -4, so z = -1.

Next, multiply the 3rd equation by 2:  You'll get -2x + 2y + 2z = -2.

Add this result to the first equation.  The 2x terms will cancel, leaving you with the system

2y + 2z = -2
  y  +  z  = 4

This would be a good time to subst. -1 for z.  We then get:

-2y - 2 = -2.  Then y must be 0.  y = 0.

Now subst. -1 for z and 0 for y in any of the original equations.

For example, x - (-1) + 3(0) = -2, so x + 1 = -2, or x = -3.

Then a tentative solution is     (-3, -1, 0).

It's very important that you ensure that this satisfies all 3 of the originale quations.
5 0
4 years ago
If AC=3x, AB=15, and BC=2x-1, how could we solve for x? A. Set 3x=15 B. Set 3x=2x-1 C. Set 3x+15=2x-1 D. Set 3x=15+ (2x-1) E. No
k0ka [10]
Hmm this is a very challenging question good luck finding someone who can answer it lol
5 0
3 years ago
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