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NeX [460]
3 years ago
9

An athlete runs 600 m in 2 minutes and the next 1000 m in 1 minute on the same straight

Physics
1 answer:
krek1111 [17]3 years ago
3 0

Answer:

Explanation:

Average speed is found by adding together the total distances traveled by the athlete and divide that total by the total time it took.

Average velocity is vector, which means it includes direction. If the athlete heads one way and then turns around, his displacement might actually be negative! Yikes! Let's look at speed first:

s=\frac{600+1000}{2+1}=\frac{1600}{3}=533\frac{1}{3}\frac{m}{min}

Velocity is the displacements added together divided by the total amount of time it took. The displacement is the same as the distance here, since the athlete did not veer off his straight-path and didn't turn around.

Average velocity = average speed = 533.3 m/min

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Puck B has twice the mass of puck A. Starting from rest, both pucks are pulled the same distance across frictionless ice by stri
gogolik [260]

Answer:

(a) 1 : 2

(b) same

Explanation:

Let the mass of puck A is m and the mass of puck B is 2 m.

initial speed for both the pucks is same as u and the distance is same for both is s.

let the tension is T for same.

The kinetic energy is given by

K = 0.5 mv^2

(a) As the speed is same, so the kinetic energy depends on the mass.

So, kinetic energy of A : Kinetic energy of B = m : 2m  = 1 : 2

(b) A the distance s same so the final velocities are also same.

8 0
3 years ago
A car with a total mass of 1800 kg (including passengers) is driving down a washboard road with bumps spaced 4.9 m apart. The ri
Drupady [299]

Answer:

k = 9.6 x 10^5 N/m or 9.6 kN/m

Explanation:

First, we need to use the expression to calculate the spring constant which is:

w² = k/m

Solving for k:

k = w²*m

To get the angular velocity:

w = 2πf

The problem is giving the linear velocity of the car which is 5.7 m/s. With this we can calculate the frequency of the car:

f = V/x

f = 5.7 / 4.9 = 1.16 Hz

Now the angular velocity:

w = 2π*1.16

w = 7.29 rad/s

Finally, solving for k:

k = (7.29)² * 1800

k = 95,659.38 N/m

In two significant figures it'll ve 9.6 kN/m

5 0
3 years ago
Read 2 more answers
How much tension must a rope withstand if it is used to accelerate a 6526 kg car vertically upwards at 8.9 m/s^2?
ExtremeBDS [4]

Answer:

The value is T =  122036.2 \  N

Explanation:

From the question we are told that

     The mass of the car is  m  = 6526 \  kg

      The acceleration  is  a=  8.9 \  m/s^2

Generally the net force applied on the rope is mathematically represented as

          F_{net}   =  T -  W

Here W is the weight of the car which is evaluated as

         W =  m * g

=>      W =  6526  * 9.8

=>       W =  63954.8 \  N

Generally the net force can also be mathematically represented as

       F =  m * a

So

        m * a  =  T  -  63954.8

=>     6526  *  8.9 =  T  -  63954.8

=>      T =  122036.2 \  N

7 0
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What happens when infrared hits a shiny surface
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Will reflect ........
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Is it not standard deviation? or am i just dumb lol
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