Assuming the friction between the skaters and the ice is negligible, the magnitude of Porsha's acceleration is 2.8m/s².
Missing part of the question: determine the magnitude of Porsha's acceleration.
Given the data in the question;
- Mass of Porsha;

- Mass of Zorn;

- Force of Porsha push;

Magnitude of Porsha's acceleration; 
To determine the magnitude of Porsha's acceleration, we use Newton's second laws of motion:

Where m is the mass of the object and a is the acceleration.
We substitute the mass of Porsha and the force he used into the equation
Therefore, assuming the friction between the skaters and the ice is negligible, the magnitude of Porsha's acceleration is 2.8m/s².
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Answer:
Explanation:
Given
mass of marble 
velocity of marble 
mass of second marble 
Velocity of second marble 
After collision 13.5 gm marble moves to the right at i.e. 
Conserving momentum





Answer:
700,000g
Explanation:
1kg = 1000 Grams (or any kg x 1000)
Answer: 9.9%
Explanation: efficiency = (work output /work input) × 100
Note that, 1 kilocalorie = 4184 joules, hence 22kcal = 22× 4184 = 92048 joules.
Work output = 9200 j and work input = 92048 j
Efficiency = (9200/92048) × 100 = 0.099 × 100 = 9.9%
It should be 0.25kg because you converter from g to kg and since 1g<1kg so you move the decimal to the left