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2 years ago

Can you plz make me brainliast?

Physics

1 answer:

bekas [8.4K]2 years ago

8 0

Answer:

I dont know what to answer so im just gonna say ok

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Zorn and Porsha are ice skating. Porsha has a mass of 60 kg, and Zorn has a mass of 40 kg. As they face each

algol13

Assuming the friction between the skaters and the ice is negligible, the magnitude of Porsha's acceleration is 2.8m/s².

Missing part of the question: determine the magnitude of Porsha's acceleration.

Given the data in the question;

Mass of Porsha; $m_{porsha} = 60kg$

Mass of Zorn; $m_{zorn} = 40kg$

Force of Porsha push; $F_{porsha} = 168N$

Magnitude of Porsha's acceleration; $a = \ ?$

To determine the magnitude of Porsha's acceleration, we use Newton's second laws of motion:

$F = m*a$

Where m is the mass of the object and a is the acceleration.

We substitute the mass of Porsha and the force he used into the equation

$168N = 60kg * a\\\\a = \frac{168kg.m/s^2}{60kg}\\\\a = 2.8m/s^2$

Therefore, assuming the friction between the skaters and the ice is negligible, the magnitude of Porsha's acceleration is 2.8m/s².

Learn more: brainly.com/question/25125444

3 0

3 years ago

A 27.0 g marble sliding to the right at 56.8 cm/s overtakes and collides elastically with a 13.5 g marble moving in the same dir

Nataly [62]

Answer: $v_1=28.4 cm/s$

Explanation:

Given

mass of marble $m_1=27 gm$

velocity of marble $u_1=56.8 cm/s \approx 0.568 m/s$

mass of second marble $m_2=13.5 gm$

Velocity of second marble $u_2=14.2 cm/s \approx 0.142 m/s$

After collision 13.5 gm marble moves to the right at i.e. $v_2=71 cm/s$

Conserving momentum

$m_1u_1+m_2u_2=m_1v_1+m_2v_2$

$27\times 56.8+13.5\times 14.2=27\times v_1+13.5\times 71$

$1533.6+191.7=27\cdot v_1+958.5$

$27\cdot v_1=766.8$

$v_1=\frac{766.8}{27}=28.4 cm/s$

7 0

3 years ago

Convert 700kg into grams<br>

Verdich [7]

Answer:

700,000g

Explanation:

1kg = 1000 Grams (or any kg x 1000)

5 0

2 years ago

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A heat engine does 9200 J of work per cycle while absorbing 22.0 kcal of heat from a hightemperature reservoir. What is the effi

Morgarella [4.7K]

Answer: 9.9%

Explanation: efficiency = (work output /work input) × 100

Note that, 1 kilocalorie = 4184 joules, hence 22kcal = 22× 4184 = 92048 joules.

Work output = 9200 j and work input = 92048 j

Efficiency = (9200/92048) × 100 = 0.099 × 100 = 9.9%

4 0

3 years ago

In an experiment, you find the mass of a cart to be 250 grams. What is the mass of the cart in kilograms?

gizmo_the_mogwai [7]

It should be 0.25kg because you converter from g to kg and since 1g<1kg so you move the decimal to the left

5 0

3 years ago

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