Explanation:
It is given that,
Radius of curvature of the mirror, R = 1.54 cm
(a) We have to find the focal length of the mirror. The relationship between the focal length and the radius of curvature is given by :

f = focal length of the mirror

f = 0.77 cm
(b) The power of mirror is given by the reciprocal of focal length i.e.
Power, 
P = 1.29 diopters
Hence, this is the required solution.
Answer:
Se llama ángulo de incidencia -i- el formado por el rayo incidente y la normal. La normal es una recta imaginaria perpendicular a la superficie de separación de los dos medios en el punto de contacto del rayo. El ángulo de reflexión -r- es el formado por el rayo reflejado y la normal.
Answer:
585lb
Explanation:
Given the following
F1 = 235lb
F2 = 350lb
The resultant is expressed as;
FR = F1+F2
Substitute the given values
FR = 235+350
FR = 585lb
Hence the magnitude of the resultant is 585lb
Answer:
they both exert the same pressure
Explanation:
Pressure is the ratio of force to area. It is given as:
, where F is the force, P is pressure and A is area
1) For the cuboid, the area of the base placed on the ground (A) = 8 cm × 3 cm = 24 cm² = 0.0024 m². Therefore the pressure is:

2) For the cube, the area of the base placed on the ground (A) = 4 cm × 4 cm = 16 cm² = 0.0016 m². Therefore the pressure is:

Therefore, they both exert the same pressure.