Ask question

Ask question

All categories

2 years ago

11

The Johnson family had a 4,392-gallon swimming pool installed last month. They are filling the pool at a rate of 2 pints per sec

ond. How fast are they filling the pool in gallons per day?

2 answers:

Llana [10]2 years ago

7 0

they are filling the pool every minute

asambeis [7]2 years ago

7 0

2 pints=0.25 gallons
1 day=86400 seconds

0.25/sec=g/86400

g=86400x0.25/1
=21600 gallons per day

The Johnson family are filling 21600 gallons per day.

You might be interested in

Wanni cycled 6 km from her house to the school at a uniform speed, v km/h. If she increased her speed

Karolina [17]

Answer:

The quadratic equation in terms of v is v² + 2 v + 180 = 0

Step-by-step explanation:

Given as :

The distance between house to the school = d = 6 km

The uniform speed = v km/h

So, Time = $\dfrac{\textrm Distance}{\textrm speed}$

or, t = $\dfrac{\textrm d}{\textrm v}$

Or, t = $\dfrac{\textrm 6}{\textrm v}$

<u>Now, Again</u>

The speed is increase by 2 km/h

i.e speed = (v + 2) km/h

So, Time taken = t' = (t - $\dfrac{4}{60}$ )hours

i.e t' = (t - $\dfrac{1}{15}$ )hours

Now, Time = $\dfrac{\textrm Distance}{\textrm speed}$

So, (t - $\dfrac{1}{15}$ ) = $\dfrac{\textrm d}{\textrm v}$

Or, (t - $\dfrac{1}{15}$ ) = $\dfrac{\textrm 6}{\textrm (v + 2)}$

Or , $\dfrac{\textrm 6}{\textrm v}$ - $\dfrac{1}{15}$ = $\dfrac{\textrm 6}{\textrm (v + 2)}$

Or , $\dfrac{\textrm 90 - v}{\textrm 15 v}$ = $\dfrac{\textrm 6}{\textrm v + 2}$

Or, (90 - v) × (v + 2) = 6 × 15 v

Or, 90 v - 180 - v² - 2 v = 90 v

Or, v² + 2 v + 180 = 90 v - 90 v

Or, v² + 2 v + 180 = 0

So, The quadratic equation in terms of v

v² + 2 v + 180 = 0

Hence The quadratic equation in terms of v is v² + 2 v + 180 = 0 Answer

3 0

3 years ago

Line AB contains points A (8, −4) and B (1, −5). The slope of line AB is....

shutvik [7]

Answer:

$The\ slope\ of\ the\ line\ AB\ is \frac{1}{7} .$

Step-by-step explanation:

Formula for slope

$m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$

As the Line AB contains points A (8, −4) and B (1, −5).

Put points value in the above

$m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$

$m = \frac{- 5- (-4)}{1 - 8}$

$m = \frac{- 5 + 4}{1 - 8}$

$m = \frac{- 1}{-7}$

$m = \frac{1}{7}$

$Therefore\ the\ slope\ of\ the\ line\ AB\ is \frac{1}{7} .$

7 0

3 years ago

Read 2 more answers

Taking a quiz plz help

Burka [1]

Answer:

Show the whole photo and you will maybe get help

Step-by-step explanation:

3 0

2 years ago

You are playing the slot machine. There are 3 wheels and each wheel has a picture of 7 different fruit (lemon, plum, apple, oran

S_A_V [24]

Here are the outcomes. You could also a tree diagram for this:

There are 49 outcomes for this problem. Therefore, 7/49 possible probability that 2 could be orange. To check if i'm correct, use a tree diagram or a compound principle.

8 0

3 years ago

A survey collected data on annual credit card charges in seven different categories of expenditures: transportation, groceries,

Andru [333]

Answer:

A. Null and alternative hypothesis:

$H_0: \mu_d=0\\\\H_a:\mu_d\neq 0$

B. Yes. At a significance level of 0.05, there is enough evidence to support the claim that there is signficant difference between the population mean credit card charges for groceries and the population mean credit card charges for dining out.

P-value = 0.00002

C. As the difference is calculated as (population 1 − population 2), being population 1: groceries and population 2: dinning out, and knowing there is evidence that the true mean difference is positive, we can say that the groceries annual credit card charge is higher than dinning out annual credit card charge.

The point estimate is the sample mean difference d=$840.

The 95% confidence interval for the mean difference between the population means is (490, 1190).

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that there is signficant difference between the population mean credit card charges for groceries and the population mean credit card charges for dining out.

Then, the null and alternative hypothesis are:

$H_0: \mu_d=0\\\\H_a:\mu_d\neq 0$

The significance level is 0.05.

The sample has a size n=42.

The sample mean is M=840.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=1123.

The estimated standard error of the mean is computed using the formula:

$s_M=\dfrac{s}{\sqrt{n}}=\dfrac{1123}{\sqrt{42}}=173.2827$

Then, we can calculate the t-statistic as:

$t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{840-0}{173.2827}=\dfrac{840}{173.2827}=4.848$

The degrees of freedom for this sample size are:

$df=n-1=42-1=41$

This test is a two-tailed test, with 41 degrees of freedom and t=4.848, so the P-value for this test is calculated as (using a t-table):

$\text{P-value}=2\cdot P(t>4.848)=0.00002$

As the P-value (0.00002) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

At a significance level of 0.05, there is enough evidence to support the claim that there is signficant difference between the population mean credit card charges for groceries and the population mean credit card charges for dining out.

We have to calculate a 95% confidence interval for the mean difference.

The t-value for a 95% confidence interval and 41 degrees of freedom is t=2.02.

The margin of error (MOE) can be calculated as:

$MOE=t\cdot s_M=2.02 \cdot 173.283=350$

Then, the lower and upper bounds of the confidence interval are:

$LL=M-t \cdot s_M = 840-350=490\\\\UL=M+t \cdot s_M = 840+350=1190$

The 95% confidence interval for the mean difference is (490, 1190).

7 0

2 years ago