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ANTONII [103]
3 years ago
14

Sweat is made up of all EXCEPT what? * A.Sugar B.Salt C.Urea D.Urine

Chemistry
1 answer:
andreev551 [17]3 years ago
8 0
D, Urine.

Just google what sweat is made of and it gives you all of the answers except for urine. Also you’d probably smell really bad if your sweat had urine in it. Hope this helps! :)
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What word is used to refer to a group of organ systems working together?
kotegsom [21]

Answer:

1

Explanation:

in my opinion,The answer would be organism

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6 0
3 years ago
A gas is contained in a thick-walled balloon. When the pressure change from 100 kPa to 90.0 kPa, the volume changes from 2.50 L
Orlov [11]
The  temperature  change is   calculated using the  combined  gas law
that  is P1V1/T1  =P2V2/T2
P1=  100KPa
P2=90kpa
v1= 2.50 L
v2= 3.75 L
T1= 303 K
T2=?

T2  is  therefore  =  P2V2T1/P1V1
=( 90  x 3.75  x303)/  (100  x2.50) =  409.05  K
3 0
3 years ago
Read 2 more answers
Suppose 0.245 g of sodium chloride is dissolved in 50. mL of a 18.0 m M aqueous solution of silver nitrate.
Bezzdna [24]

Answer:

\large \boxed{\text{ 0.066 mol/L}}

Explanation:

We are given the amounts of two reactants, so this is a limiting reactant problem.

1. Assemble all the data in one place, with molar masses above the formulas and other information below them.

Mᵣ:       58.44  

            NaCl + AgNO₃ ⟶ NaNO₃ + AgCl

m/g:     0.245

V/mL:                 50.

c/mmol·mL⁻¹:       0.0180

2. Calculate the moles of each reactant  

\text{Moles of NaCl} = \text{245 mg NaCl} \times \dfrac{\text{1 mmol NaCl}}{\text{58.44 mg NaCl}} = \text{4.192 mmol NaCl}\\\\\text{ Moles of AgNO}_{3}= \text{50. mL AgNO}_{3} \times \dfrac{\text{0.0180 mmol AgNO}_{3}}{\text{1 mL AgNO}_{3}} = \text{0.900 mmol AgNO}_{3}

3. Identify the limiting reactant  

Calculate the moles of AgCl we can obtain from each reactant.

From NaCl:  

The molar ratio of NaCl to AgCl is 1:1.

\text{Moles of AgCl} = \text{4.192 mmol NaCl} \times \dfrac{\text{1 mmol AgCl}}{\text{1 mmol NaCl}} = \text{4.192 mmol AgCl}

From AgNO₃:  

The molar ratio of AgNO₃ to AgCl is 1:1.  

\text{Moles of AgCl} = \text{0.900 mmol AgNO}_{3} \times \dfrac{\text{1 mmol AgCl}}{\text{1 mmol AgNO}_{3}} = \text{0.900 mmol AgCl}

AgNO₃ is the limiting reactant because it gives the smaller amount of AgCl.

4. Calculate the moles of excess reactant

                   Ag⁺(aq)  +  Cl⁻(aq) ⟶ AgCl(s)

 I/mmol:      0.900        4.192            0

C/mmol:    -0.900       -0.900        +0.900

E/mmol:      0                3.292          0.900

So, we end up with 50. mL of a solution containing 3.292 mmol of Cl⁻.

5. Calculate the concentration of Cl⁻

\text{[Cl$^{-}$] } = \dfrac{\text{3.292 mmol}}{\text{50. mL}} = \textbf{0.066 mol/L}\\\text{The concentration of chloride ion is $\large \boxed{\textbf{0.066 mol/L}}$}

8 0
3 years ago
A laser is used in eye surgery to weld a detached retina back into place. The wavelength of the laser beam is 503 nm, while the
V125BC [204]

Answer:

Number of proton emmitted by laser=2.48*10^17proton

Explanation:

Energy is the ability to cause change; power is directly proportional to energy and its the rate energy is utilized.

Power=energy/time.

First we need to calculate the total energy used which is equal to the total power utilized.

E(total)= P( total) = 1.4W × 0.070 s =0.098J

CHECK THE ATTACHMENT FOR THE REMAINING DETAILED CALCULATION

4 0
4 years ago
When a material changes state, what happens to the bonds between the molecules?
brilliants [131]

Answer:

<em>When </em><em>a </em><em>substance</em><em> </em><em>is </em><em>cooled </em><em>it's </em><em>internal </em><em>energy</em><em> </em><em>decreases</em><em> </em><em>the </em><em>movement</em><em> </em><em>of </em><em>its </em><em>partical</em><em> </em><em>decreases </em><em>the </em><em>bonds </em><em>between </em><em>particles </em><em>form </em><em>when </em><em>a </em><em>substance </em><em>condenses </em><em>or </em><em>freezes </em><em>or </em><em>sublimes </em><em>to </em><em>form </em><em>a </em><em>solid </em><em>from </em><em>a </em><em>gas </em>

<em><u>may </u></em><em><u>be </u></em><em><u>this </u></em><em><u>might </u></em><em><u>help </u></em><em><u>u</u></em>

6 0
3 years ago
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