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nlexa [21]
3 years ago
6

Compared to the boiling point and the freezing point of water at 1 atmosphere, a 1.0 M CaCl2(aq) solution at 1 atmosphere has a

Chemistry
2 answers:
loris [4]3 years ago
6 0

Answer:

The is a higher boiling

point and lower freezing point

Explanation:

Vlada [557]3 years ago
4 0

Answer:

Higher boiling point and lower freezing point

Explanation:

Boiling point is the temperature at which substances goes to gaseous phase form their liquid phase. Liquids boil when vapour pressure of the liquid becomes equal to atmospheric pressure. So boiling point of a liquid is affected by the change in its vapour pressure and vapour pressure is affected by adding a non-volatile solute in it.

Effect of adding non -volatile solute on vapour pressure:

When a non-volatile solute is added to a liquid, it alters the interaction between the liquid particles and prevents the liquid particles to going into gaseous phase which results in decrease in vapour pressure. More energy is needed for the vapour pressure of the liquid to becomes equal to atmospheric pressure. Therefore, boiling point increases.

CaCl2 is a non-volatile solute and hence increases the boiling point of the water.

Effect of adding non-volatile solute on freezing point:

When a non-volatile solute is added to a liquid, it alters the interaction between the liquid molecules. The new solute and solvent interaction prevents the liquid to soldify and requires more lowering in temperature. Therefore, freezing point decreases.

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Why do scientists use spiral tubes instead of straight ones?
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Answer:

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4 0
3 years ago
Be sure to answer all parts. find the molar solubility of bacro4 (ksp= 2.1 × 10−10) in (a) pure water × 10 m (b) 1.6 × 10−3 m na
Vlad [161]
A) in pure water :

by using ICE table:

According to the reaction equation:

            BaCrO4(s)    →  Ba^2+(aq)    +   CrO4^2-(aq)

initial                               0                          0

change                          +X                       +X 

Equ                                  X                         X


when Ksp = [Ba^2+][CrO4^2-]

by substitution:

2.1 x 10^-10 = X* X

∴X = √2.1 x 10*-10

∴X = 1.4 x 10^-5

∴ the solubility = X = 1.4 X 10^-5

B) In 1.6 x 10^-3 m Na2CrO4

 by using ICE table:

According to the reaction equation:

            BaCrO4(s)  →  Ba^2+(aq)    +   CrO4^2-(aq)

initial                                 0                      0.0016

Change                           +X                      +X

Equ                                   X                      X+0.0016

when Ksp = [Ba^2+][CrO4^2-]

by substitution:

2.1 x 10^-10 = X*(X+0.0016) by solving for X 

∴ X = 1.3 x 10^-7

∴ solubility =X = 1.3 x 10^-7

3 0
3 years ago
2. Which equation shows the relationship between the Kelvin and Celsius temperature scales?
givi [52]

Answer: I think the right answer is c

7 0
3 years ago
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