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2 years ago

Watch help video

Mathematics

1 answer:

amm18122 years ago

4 0

Answer:

Step-by-step explanation:

25 - 32 = -7 and 18 - 25 = -7

It means an arithmetic sequence with common difference d = -7

$a_n = a_1+d(n-1)\\\\a_1=32\\d=-7\\\\a_n=32+(-7)(n-1)\\\\a_n = 32-7n+7\\\\\underline{a_n=-7n+39}$

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Barbara mixes 54 ounces of granola and 36 ounces of raisins.She divides the mixture into 6 ounce servings.How many servings does

Sindrei [870]

Hello!

If Barbara mixes 54 ounces of granola and 36 ounces of raisins, the overall mixture will equal 90 ounces. In order to find the amount of servings that Barbara makes, we must divide the total number by the other number given - 6.
Because Barbara wants to divide the mixture into 6 ounce servings, we will divide 90 by 6.
90/6=15

The answer to your question is "Barbara made 15 6-ounce servings."

I hope this helps you! Have a great day!

6 0

3 years ago

Simplify (3x^2)^6 PLZ I NEED IT FAST! I WILL GIVE BRAINLIEST!

Levart [38]

Answer:

729x^12

Step-by-step explanation:

3x^2*3x^2*3x^2*3x^2*3x^2*3x^2

5 0

2 years ago

If (y) varies directly with x, and y=3 when x=0.2, what is the value of (y) when x=1?

Luba_88 [7]

_Brainliest if helped!!

since it varies directly, we form an equation ,
Y =kX where k is a constant
use the points given to find K ,
3 =0.2k , k = 15

So to get final answer,

when x = 1
y = kx, = 1(15)
y= 15

Hence when x=1, < y = 15 >

4 0

3 years ago

Read 2 more answers

Two truckers leave from the same point driving in opposite directions, the first trucker driving at 62 miles per hour and the s

Elodia [21]

Answer:

1 hour 42 minutes

Step-by-step explanation:

Given: Speed of 1st trucker= 62 mph

Speed of 2nd trucker= 66 mph

Total distance need to cover to be in contact is 270 miles

1st trucker start 1 hour ahead of 2nd trucker

Lets assume 2nd trucker take `x` hours to be in contact and 1st trucker take `(x+1)` hours.

We know, distance= $speed\times time$

1st trucker, distance $(d_1)= 62\times (x+1)$

∴ $d_1= 62x+62$

2nd trucker, distance $(d_2)= 66\times x$

∴ $d_2= 66x$

Now, putting the values in an equation.

$d_1+d_2= 270$

⇒ $(62x+62)+66x= 270$

Opening the parenthesis to solve and subtracting both side by 62

⇒ $122x= 208$

∴ x= $\frac{208}{122} = 1.70\ h$ = 1 hour 42 minutes

∴ It will take 1 hour 42 minutes to be able contact each other after first trucker leaves.

3 0

3 years ago

An eastbound train left at 12pm. Four hours later, a westbound train left the same station. At 8pm, the two trains were 400 mile

Ainat [17]

Answer:

Step-by-step explanation:

Gotta love these motion problems!

d = rt is what we need here to solve this, along with some logic.

If the EB (eastbound) train left at noon then at the end of its travels, at 8pm to be specific, it was traveling for 8 hours. Therefore, for the EB train, t = 8.

If the WB train left at 4 pm then at the end of its travels, also at 8pm, it was traveling for 4 hours. Therefore, for the WB train, t = 4.

The distance between the trains is given as 400 miles. That 400 mile distance is due to the fact that each train traveled a distance of rate*time. The distance the WB train traveled + the distance the EB train traveled = 400 miles. Now we just need to find out the distance each traveled in its respective time frame.

For the EB train. We already know that t = 8. We do not know how fast it's going, so rate is just r. In the distance formula, d = rt:

$d_{EB}=8r$

For the WB train. We already know that t = 4. We do not know this rate either, but we do know that it is traveling 10 mph faster than the EB train, so rate is r + 10. In the distance formula, d = rt:

$d_{WB}=4(r+10)$ and