Answer:
About .42
Step-by-step explanation:
The first thing we are going to do for this case is define variables.
We have then:
y = the cost of the box
x = one side of the square base
z = height of the box
The volume of the building is 14,000 cubic feet:
x ^ 2 * z = 14000
We cleared z:
z = (14000 / x ^ 2)
On the other hand, the cost will be:
floor = 4 (x ^ 2)
roof = 3 (x ^ 2)
for the walls:
1 side = 16 (x * (14000 / x ^ 2)) = 16 (14000 / x)
4 sides = 64 (14000 / x) = 896000 / x
The total cost is:
y = floor + roof + walls
y = 4 (x ^ 2) + 3 (x ^ 2) + 896000 / x
y = 7 (x ^ 2) + 896000 / x
We derive the function:
y '= 14x - 896000 / x ^ 2
We match zero:
0 = 14x - 896000 / x ^ 2
We clear x:
14x = 896000 / x ^ 2
x ^ 3 = 896000/14
x = (896000/14) ^ (1/3)
x = 40
min cost (y) occurs when x = 40 ft
Then,
y = 7 * (40 ^ 2) + 896000/40
y = 33600 $
Then the height
z = 14000/40 ^ 2 = 8.75 ft
The price is:
floor = 4 * (40 ^ 2) = 6400
roof = 3 * (40 ^ 2) = 4800
walls = 16 * 4 * (40 * 8.75) = 22400
Total cost = $ 33600 (as calculated previously)
Answer:
The dimensions for minimum cost are:
40 * 40 * 8.75
Answer:
90
Step-by-step explanation:
10!/(10-2)!
n!=n(n-1)!
10•9•8!/(10-2)!
10•9•8!/8!
The 8! cancels out and you're left with 10•9
So, your answer is 90
Suppose the cost stock is x and the cost of fund is y.
Total cost of Nora's portfolio:
100x+200y=3800.....i
Total cost of Erin's portfolio
300x+50y=5350...ii
solving the simultaneous equation by elimination method we proceed as follows:
multiplying eqn by 3 and subtracting ii we get:
550y=6050
thus
y=6050/550
y=11
next, multiply ii by 4 and subtracting i we get:
1100x=17600
x=16
thus the cost of Technology stock was $16 and the cost of mutual fund was $11
