The probability the man will win will be 13.23%. And the probability of winning if he wins by getting at least four heads in five flips will be 36.01%.
<h3>How to find that a given condition can be modeled by binomial distribution?</h3>
Binomial distributions consist of n independent Bernoulli trials.
Bernoulli trials are those trials that end up randomly either on success (with probability p) or on failures( with probability 1- p = q (say))
P(X = x) = ⁿCₓ pˣ (1 - p)⁽ⁿ⁻ˣ⁾
A man wins in a gambling game if he gets two heads in five flips of a biased coin. the probability of getting a head with the coin is 0.7.
Then we have
p = 0.7
n = 5
Then the probability the man will win will be
P(X = 2) = ⁵C₂ (0.7)² (1 - 0.7)⁽⁵⁻²⁾
P(X = 2) = 10 x 0.49 x 0.027
P(X = 2) = 0.1323
P(X = 2) = 13.23%
Then the probability of winning if he wins by getting at least four heads in five flips will be
P(X = 4) = ⁵C₄ (0.7)⁴ (1 - 0.7)⁽⁵⁻⁴⁾
P(X = 4) = 5 x 0.2401 x 0.3
P(X = 4) = 0.3601
P(X = 4) = 36.01%
Learn more about binomial distribution here:
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Answer:
91/18
Step-by-step explanation:
A = s2 (Area of a square is its side squared)
P = 4s (perimeter of a square is a side times 4)
A = 324 (the area of this square is 324 ft2)
fencing = $7 per foot
Let's find the side through the area. Find the root:
√324 = √s2
18 = s
Now the perimeter:
P = 4 * 18 = 72
Now to find how much the fencing will cost:
72 * 7 = 504
Answer: who ever arrives at the answer x=0/3 =0 is correct
Step-by-step explanation:
Even though I need supporting details from the individual answers of Jane and Jill to pass my own judgment.
Given the expression
(2x²+x) +2(-x²+×)=0
Let's us open the bracket
2x²+x-2x²+2x=0
Collecting like terms
2x²-2x²+x+2x=0
3x=0
x=0/3
x=0
X is equal to zero is what I got.
