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Ede4ka [16]
3 years ago
6

How much is 106 divided by 6? A) 17 R2 B)17 R3 C)17 R4 D)17 R1​

Mathematics
1 answer:
musickatia [10]3 years ago
7 0

Answer:

C, 17 R4.

Step-by-step explanation:

6x17 is equal to 102, and 102+4 gets you to 106, therefor C is the correct answer.

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Help me pls & thanksss
lbvjy [14]

Answer:

135 degrees.

Step-by-step explanation:

Assuming that it is a regular octagon, you can use the formula (n-2) (180) divided by n. n = sides. Therefore, (8-2) (180) divided by 8, which is 135.

3 0
3 years ago
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An education center offers a total of 400 math, physics and
mihalych1998 [28]

Answer: 30

Step-by-step explanation:

3+4+3=10 400/10=40 so each has 40 so math has 120 120*25=3000 for physics is 4*40 so 160 160*20=3200 9800-3000-3200=3600 3*40=120 3600/120=30

3 0
3 years ago
Slope is 5, and (2,6) is on the line
tigry1 [53]
Y - 6= 5(x - 2)

y - 6 = 5x - 10
y= 5x - 4

3 0
3 years ago
Find the slope-intercept equation of the line that<br> passes through (0,4) and has a slope of 1.
rodikova [14]

Answer:

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4 0
3 years ago
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A 2?-ft wide circular track for a camera dolly is set up for a movie scene. The two rails of the track form concentric circles.
navik [9.2K]

Answer: A wheel on the outer rail travel 12.57 ft more than a wheel on the inner rail of the track.

Step-by-step explanation:

Since we have given that

Radius of inner circle = 57 ft

As we know the formula for "Circumference of circle":

Distance=Circumference=2\pi r\\\\Distance=2\times \frac{22}{7}\times 57\\\\Distance=358.28\ Ft

Since we have also mentioned that there is 2 feet wide circular track for a camera dolly.

So, Radius of outer circle will be given as

57+2\\=59\ ft

So, Distance = Circumference is given by

Distance=2\pi R\\\\Distance=2\times \frac{22}{7}\times 59\\\\Distance=370.85\ ft

Hence, Difference between the outer rail travel than a wheel on the inner rail travel is given by

370.85-358.28\\\\=12.57\ ft

Therefore, A wheel on the outer rail travel 12.57 ft more than a wheel on the inner rail of the track.

7 0
3 years ago
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