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3 years ago

The graph of y= x^2 +4x +3 is shown work out a and b please

Mathematics

2 answers:

sdas [7]3 years ago

3 0

Answer:

A.) i think it's (-2, -1)

B.) ?

Step-by-step explanation:

I am very sorry if they are wrong....i don't know B..sorry

Licemer1 [7]3 years ago

3 0

Answer:

b = (-1,0) (-3,0)

Step-by-step explanation:

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Two less than four times a number is 6

iris [78.8K]

Answer: 2 - 4x = 6

Please mark me as brainliest

5 0

3 years ago

Does anyone know the answer?

motikmotik

Answer:

We conclude that the area of the right triangle is:

$A\:=p^2-2p-3$

Hence, option A is correct.

Step-by-step explanation:

From the given right-angled triangle,

Base = p+1

Perpendicular = 2p-6

Using the formula to determine the area of the right-angled triangle

Area of the right triangle A = 1/2 × Base × Perpendicular

$=\frac{1}{2}\left(p+1\right)\left(2p-6\right)$

Factor 2p-6: 2(p-3)

$=\frac{\left(p+1\right)\times \:2\left(p-3\right)}{2}$

Divide the number: 2/2 = 1

$=\left(p+1\right)\left(p-3\right)$

$\mathrm{Apply\:FOIL\:method}:\quad \left(a+b\right)\left(c+d\right)=ac+ad+bc+bd$

$=pp+p\left(-3\right)+1\cdot \:p+1\cdot \left(-3\right)$

$=pp-3p+1\cdot \:p-1\cdot \:3$

$=p^2-2p-3$

Therefore, we conclude that the area of the right triangle is:

$A\:=p^2-2p-3$

Hence, option A is correct.

3 0

3 years ago

3. Arrange these numbers from least to greatest. <br> -2.5<br> -1/3 1.7 27/4 -0.9

Svet_ta [14]

Answer: -2.5,, -0.9,, -1/3,, 1.7,, 27/4

Step-by-step explanation:

6 0

3 years ago

A:<br> What is 7*<img src="https://tex.z-dn.net/?f=10%5E%7B15%7D" id="TexFormula1" title="10^{15}" alt="10^{15}" align="absmiddl

pickupchik [31]

Step-by-step explanation:

7*10^10=70,000,000

(70milion)

7*10^15=7000,000,000,000,000

3 0

3 years ago

Give the properties for the equation -2x 2 - y + 10x - 7 = 0.

Sladkaya [172]

Given:

The quadratic equation is

$-2x^2-y+10x-7=0$

To find:

The vertex of the given quadratic equation.

Solution:

If a quadratic function is $f(x)=ax^2+bx+c$ , then

$Vertex=\left(\dfrac{-b}{2a},f(\dfrac{-b}{2a})\right)$

We have,

$-2x^2-y+10x-7=0$

It can be written as

$-2x^2+10x-7=y$

$y=-2x^2+10x-7$ ...(i)

Here, $a=-2,b=10,c=-7$ .

$\dfrac{-b}{2a}=\dfrac{-10}{2(-2)}$

$\dfrac{-b}{2a}=\dfrac{-10}{-4}$

$\dfrac{-b}{2a}=\dfrac{5}{2}$

Putting $x=\dfrac{5}{2}$ in (i), we get

$y=-2(\dfrac{5}{2})^2+10(\dfrac{5}{2})-7$

$y=-2(\dfrac{25}{4})+\dfrac{50}{2}-7$

$y=\dfrac{-50}{4}+25-7$

$y=\dfrac{-25}{2}+18$

On further simplification, we get

$y=\dfrac{-25+36}{2}$

$y=\dfrac{11}{2}$

So, the vertex of the given quadratic equation is $\left(\dfrac{5}{2},\dfrac{11}{2}\right)$ .

Therefore, the correct option is A.

3 0

3 years ago