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zubka84 [21]
3 years ago
5

In ΔRST, s = 620 cm, r = 210 cm and ∠R=17°. Find all possible values of ∠S, to the nearest 10th of a degree.

Mathematics
1 answer:
qaws [65]3 years ago
4 0

Answer:

1843:6754.9709254546.,657675

Step-by-step explanation:

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Given that abc is congruent to def, ac=21x-19 and df=3x+17 solve for x
rewona [7]
21x-19=3x+17 
18x=36
x=2
5 0
3 years ago
What is the answer to this equation?
Bezzdna [24]
19c is the correct answer
6 0
3 years ago
Given the graph, find the distance of GH. Round to the nearest tenth.
lord [1]

Answer:

GH = 6.3 units

Step-by-step explanation:

Assuming that 1 box represents 1 unit, the coordinate pair of G = (-2, -3), while H = (0, 3).

Distance between G and H = d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Let,

G(-2, -3) = (x_1, y_1)

H(0, 3) = (x_2, y_2)

GH = \sqrt{(0 - (-2))^2 + (3 - (-3))^2}

GH = \sqrt{(2)^2 + (6)^2}

GH = \sqrt{4 + 36} = \sqrt{40}

GH = 6.3 units (nearest tenth)

5 0
3 years ago
What is the square root of 95.54
vladimir2022 [97]
Well this is simple a calculator type problem...but if you are curious as the the algorithm used by simple calculators and such...

They use a Newtonian approximation until it surpasses the precision level of the calculator or computer program..

A newtonian approximation is an interative process that gets closer and closer to the actual answer to any mathematical problem...it is of the form:

x-(f(x)/(df/dx))

In a square root problem you wish to know:

x=√n  where x is the root and n is the number

x^2=n

x^2-n=0

So f(x)=x^2-n and df/dx=2x so using the definition of the newton approximation you have:

x-((x^2-n)/(2x)) which simplifies further to:

(2x^2-x^2+n)/(2x)

(x^2+n)/(2x), where you can choose any starting value of x that you desire (though convergence to an exact (if possible) solution will be swifter the closer xi is to the actual value x)

In this case the number, n=95.54, so a decent starting value for x would be 10.

Using this initial x in (x^2+95.54)/(2x) will result in the following iterative sequence of x.

10, 9.777, 9.774457, 9.7744565, 9.7744565066299210578124802523397

The calculator result for my calc is: 9.7744565066299210578124802523381

So you see how accurate the newton method is in just a few iterations. :P


5 0
3 years ago
Hi there can anyone help me out with this please
matrenka [14]
Simple interest,
FV=P(1+ni)
FV=future value=2500
P=present value, invested amount
n=number of years, =3
i=annual interest rate, =0.095
2500=P(1+3(0.095))
Solve for P.
8 0
3 years ago
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