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viva [34]
3 years ago
5

Find the sumofthe geometrical progression of five terms, of which the first term is 7 and the multiplier is 7.Verify that the su

m isthe product of 2801 and 7.
Mathematics
1 answer:
777dan777 [17]3 years ago
7 0

Answer:

The sum of first five term of GP is 19607.

Step-by-step explanation:

We are given the following in the question:

A geometric progression with 7 as the first term and 7 as the common ration.

a, ar, ar^2,...\\a  = 7\\r = 7

7, 7^2, 7^3, 7^4...

Sum of n terms in a geometric progression:

S_n = \displaystyle\frac{a(r^n - 1)}{(r-1)}

For sum of five terms, we put n= 5, a = 7, r = 7

S_5 = \displaystyle\frac{7(7^5 - 1)}{(7-1)}\\\\S_5 = 19607

The sum of first five term of GP is 19607.

Verification:

2801\times 7 = 19607

Thus, the sum is equal to product of 2801 and 7.

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Given the sample −4, −10, −16, 8, −12, add one more sample value that will make the mean equal to 3.
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Answer: The value to add to the set is 52

=======================================================

For a moment, ignore the extra value we'll add in later.

The given set of values add to -34.

Let x be the extra value we add in. It adds to the -34 to get -34+x, then we divide by 6 because the set {-4,-10,-16,8,-12,x} has 6 items.

So we get the mean (-34+x)/6

Set this equal to the mean we want (3) and solve for x

(-34+x)/6 = 3

-34+x = 6*3

-34+x = 18

x = 18+34

x = 52

The set {-4,-10,-16,8,-12,x} updates to {-4,-10,-16,8,-12,52} and this set has a mean of 3.

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andrew-mc [135]
What’s the expression
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To the nearest degree, what is m
LUCKY_DIMON [66]
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elogram ABCD, diagonals AC and BD intersect at point E. AE=2x, BE=y+10, CE=x+2 and DE=4y−8. Find the length of BD. A. 6 B. 16 C.
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Answer:

D

Step-by-step explanation:

The diagonals of a parallelogram bisect each other, thus

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