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UNO [17]
3 years ago
9

Select ALL the correct answers. Consider the graph of function g below. Determine which sequences of transformations could be ap

plied to the parent function f(x) = x to obtain the graph of g. shift left 2 units, reflect over the x-axis, and then vertically stretch by a factor of 3 shift down 1 unit, reflect over the x-axis, and then vertically stretch by a factor of 3 shift right 1 unit, reflect over the x-axis, and then vertically stretch by a factor of 3 reflect over the x-axis, vertically stretch by a factor of 3, and then shift down 1 unit reflect over the y-axis, vertically stretch by a factor of 3, and then shift down 1 unit shift right 1 unit, reflect over the y-axis, and then vertically stretch by a factor of 3
Mathematics
1 answer:
kaheart [24]3 years ago
7 0

Answer:

  • shift left 2 units, reflect over the x-axis, and then vertically stretch by a factor of 3

Step-by-step explanation:

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Find the number b such that the line y = b divides the region bounded by the curves y = 36x2 and y = 25 into two regions with eq
Gemiola [76]

Answer:

b = 15.75

Step-by-step explanation:

Lets find the interception points of the curves

36 x² = 25

x² = 25/36 = 0.69444

|x| = √(25/36) = 5/6

thus the interception points are 5/6 and -5/6. By evaluating in 0, we can conclude that the curve y=25 is above the other curve and b should be between 0 and 25 (note that 0 is the smallest value of 36 x²).

The area of the bounded region is given by the integral

\int\limits^{5/6}_{-5/6} {(25-36 \, x^2)} \, dx = (25x - 12 \, x^3)\, |_{x=-5/6}^{x=5/6} = 25*5/6 - 12*(5/6)^3 - (25*(-5/6) - 12*(-5/6)^3) = 250/9

The whole region has an area of 250/9. We need b such as the area of the region below the curve y =b and above y=36x^2 is 125/9. The region would be bounded by the points z and -z, for certain z (this is for the symmetry). Also for the symmetry, this region can be splitted into 2 regions with equal area: between -z and 0, and between 0 and z. The area between 0 and z should be 125/18. Note that 36 z² = b, then z = √b/6.

125/18 = \int\limits^{\sqrt{b}/6}_0 {(b - 36 \, x^2)} \, dx = (bx - 12 \, x^3)\, |_{x = 0}^{x=\sqrt{b}/6} = b^{1.5}/6 - b^{1.5}/18 = b^{1.5}/9

125/18 = b^{1.5}/9

b = (62.5²)^{1/3} = 15.75

8 0
3 years ago
What are the common factors of 24 64 88
8090 [49]

Answer is 8

8 times 3 is 24

8 times 8 is 64

8 times 11 is 88

7 0
3 years ago
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topjm [15]

Answer:

≈ 1/2 teaspoon

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Hope this helps :)

<em>ilovejiminssi♡</em>

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3 years ago
Factor the expression 3x^2+14x+8
Alex777 [14]
<span>3x^2+14x+8 = </span>(3x+2)(x+4)
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3 years ago
Find the area of Pentagon ABCDE in which BL perpendicular to AC, CM perpendicular to AD, EN perpendicular to AD such that AC = 8
deff fn [24]

Answer:

Area ABCDE = 82 cm²

Step-by-step explanation:

ABCDE = ΔEAD + ΔDAC + ΔCAB

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6 0
3 years ago
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