The coordinates of point K(7, 0).
Given, JK has midpoint M(7, 2).
And, the coordinates of point J(7, 4).
We have to find the coordinates of point K.
As M is the midpoint, therefore by using the midpoint formula.
(xₙ + yₙ) = (x₁ + x₂/2 , y₁ + y₂/2)
Using x-coordinates,
xₙ = x₁ + x₂/2
7 = x₁ + 7/2
14 = x₁ + 7
or x₁ = 7
Nos using y-coordinates,
yₙ = y₁ + y₂/2
2 = y₁ + 4/2
4 = y₁ + 4
y₁ = 0
Therefore, the coordinates of point K(7, 0).
The coordinates of J(7, 4); K(7, 0); and M(7, 2).
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The answer could be .317
(not could be as in I don't know but could be as is it's an option)
Answer:
isosceles acute
Step-by-step explanation:
two same sides so it is isosceles and all angles under 90 so acute
Answer:
DE = 6 cm
Step-by-step explanation:
Let DE = x cm.
Since DE is parallel to AB therefore by the alternate interior angles theorem, m∠BAD = m∠ADE and m∠ABE = m∠DEB ............(1)
As AD is an angle bisector of ∠A, therefore m∠EAD = m∠DAB ; Since BE is an angle bisector of ∠B ⇒ m∠ABE = m∠EBD.
Therefore, from (1) We get , m∠EAD = m∠ADE and m∠EBD = m∠BED.
So, the triangles ADE and EDB are then isosceles with AE = ED and ED = DB.
So AE = DE = DB = x, and since the perimeter of ABDE is 30 cm, then
12 + x + x + x = 30
⇒ 12 + 3x = 30
⇒ x = 6
Hence, the length of DE is 6 cm.
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(c) 4d+8 = 4(d + 2)
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