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3 years ago

4^3/2-2^3*6+8(-1)^10

Mathematics

1 answer:

Pie3 years ago

3 0

Answer:

-24

Step-by-step explanation:

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Please ignore this question!

MAXImum [283]

Ok sure , will do ..

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3 years ago

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Mrs Smith is completing a mathematics problem. She knows when 6 is added to four times a number, the result is 50. What would be

Lesechka [4]

EXPLANATION:

-To formulate an equation, you must first know what data the exercise gives us to locate them correctly.

data:

-6 that must be added to a number.

-four times a number that is equal to 4x

-a result that is equal to 50

Now with these data we formulate the equation:

$\begin{gathered} \text{Equation:} \\ 6+4x=50;\text{ } \end{gathered}$

if we solve the equation we have:

$\begin{gathered} 6\text{ }+4x=50 \\ 4x=50-6 \\ 4x=44 \\ x=\frac{44}{4} \\ x=-\frac{22}{2} \\ x=\text{ }-11 \end{gathered}$

6 0

1 year ago

How do I turn this into a radical?

dimaraw [331]

6sqrt(2) i’m pretty sure

7 0

3 years ago

Estimate the following percentages of 60 10% = ___ 25% = ___ 50% =___ 20% =___

Andrei [34K]

10% = 6
25% = 15
50% = 30
20% = 12

5 0

2 years ago

Part B

Troyanec [42]

Answer:

Part A) The length of a straight line between the school and the Fire Station is $4.6\ miles$

Part B) The length of a straight line between the school and the hospital is $2.1\ miles$

Step-by-step explanation:

The complete question in the attached figure

Let

The positive x-coordinates ----> East

The positive y-coordinates ----> North

The negative x-coordinates ----> West

The negative y-coordinates ----> South

take the point A (0,0) as the Middle School (reference point)

Part A) we have

Town Hall is located 4.3 miles directly east of the Middle School

The coordinates of Town Hall are B(4.3,0)

The Fire Station is located 1.7 miles directly North of Town Hall

The coordinates of Fire Station are C(4.3,1.7)

What is the length of a straight line between the school and the Fire Station?

Remember that

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have

A(0,0) and C(4.3,1.7)

substitute

$d=\sqrt{(1.7-0)^{2}+(4.3-0)^{2}}$

$d=\sqrt{(1.7)^{2}+(4.3)^{2}}$

$d=4.6\ miles$

Part B) we have that

The hospital is 3.1 miles west of the fire station

The coordinates of the hospital are D(4.3-3.1,1.7)

D(1.2,1.7)

What is the length of a straight line between the school and the hospital?

Remember that

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have

A(0,0) and D(1.2,1.7)

substitute

$d=\sqrt{(1.7-0)^{2}+(1.2-0)^{2}}$

$d=\sqrt{(1.7)^{2}+(1.2)^{2}}$

$d=2.1\ miles$

7 0

3 years ago