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3 years ago

4^3/2-2^3*6+8(-1)^10

Mathematics

1 answer:

Pie3 years ago

3 0

Answer:

-24

Step-by-step explanation:

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The radius of a circle is 4 feet. What is the circle's circumference?<br> r=4 ft<br> Use 3.14 for n.

Alexxandr [17]

Answer:

C = 25.12 feet

Step-by-step explanation:

C = 2 x 3.14 x 4

C = 25.12 feet

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2 years ago

Write an recursive formula for an, the nth term of the sequence 19,22,25, ....

ra1l [238]

Answer:

$T_n = T_{n-1}+3$ where n>1

Step-by-step explanation:

Given

$19,22,25, ..$

Required

Determine the recursive formula

The given sequence shows arithmetic progression (AP).

First, we calculate the common difference (d):

$d = 22 - 19 = 25 - 22$

$d = 3$

The recursive formula of an AP is determined using:

$T_n = T_{n-1}+d$ where $n>1$

Substitute 3 for d

$T_n = T_{n-1}+3$ where $n>1$

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2 years ago

Simplify the following expression: (1 point) 2x − 2y + 5z − 2x − y + 3z

Karo-lina-s [1.5K]

Answer: -3y + 8z

Step-by-step explanation:

2x -2x = 0

-2y + - y= -3y

5z + 3z= 8z

-3y + 8z

4 0

3 years ago

Read 2 more answers

A 2-digit number with x units and 7 less units than tens.

Hatshy [7]

Each two digit number has two numbers (duh!). Let's allow the tens digit to be x and the units digit to be y. Tens digit is 3 less than the units digit: x = y-3 Original number is 6 more than 4 times the sum of the digits: 10x+y-6 = 4x + 4y This gives us simultaneous equations!First let's clear the mess: 1. x= y-32. 6x-3y=6 Substitute 1 into 2: 6(y-3) -3y =66y - 18 - 3y = 6
3y = 24y = 8 Our units digit is 8 Substitute y= 8 into 1. x = y - 3x = 5 Our tens digit is 5 Therefore, our number is 58

7 0

2 years ago

Can someone help me in #66

VladimirAG [237]

$\bf log_{{ a}}(xy)\implies log_{{ a}}(x)+log_{{ a}}(y)
\\ \quad \\
% Logarithm of rationals
log_{{ a}}\left( \frac{x}{y}\right)\implies log_{{ a}}(x)-log_{{ a}}(y)
\\ \quad \\
% Logarithm of exponentials
log_{{ a}}\left( x^{{ b}} \right)\implies {{ b}}\cdot log_{{ a}}(x)\\\\
-------------------------------\\\\
$

$\bf log_4\left( \cfrac{\sqrt{x^5y^7}}{zw^4} \right)\implies log_4(\sqrt{x^5y^7})-log_4(zw^4)
\\\\\\
log_4\left[(x^5y^7)^{^\frac{1}{2}}\right]-log_4(zw^4)\implies 
\cfrac{1}{2}log_4\left[(x^5y^7)\right]-log_4(zw^4)
\\\\\\
\cfrac{1}{2}\left[ log_4(x^5)+log_4(y^7) \right] -[log_4(z)+log_4(w^4)]
\\\\\\
\cfrac{1}{2}log_4(x^5)+\cfrac{1}{2}log_4(y^7)-[log_4(z)+log_4(w^4)]$

$\bf \cfrac{1}{2}\cdot 5log_4(x)+\cfrac{1}{2}\cdot 7log_4(y)-log_4(z)-4log_4(w)
\\\\\\
\cfrac{5}{2}log_4(x)+\cfrac{7}{2}log_4(y)-log_4(z)-4log_4(w)$

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3 years ago