Given:
Angle A is 4 degrees greater than the measure of Angle B. Both angles are complementary
Complementary angles have a sum of 90°
Angle A = x + 4° ; Angle B = x
x + 4° + x = 90°
2x = 90° - 4°
2x = 86°
x = 86° ÷ 2
x = 43° ANGLE B.
Angle A = x + 4° ⇒ 43° + 4 = 47°
Given:
Angle D is 5 times the measure of Angle E. These angles are supplementary. This means that their sum is 180°
Angle D = 5x ; Angle E = x
5x + x = 180°
6x = 180°
x = 180° ÷ 6
x = 30° Angle E.
Angle D = 5x = 5(30) = 150°
6x³y + 6xy − 12x² − 12 = 6(xy-2) * (x²+1)
(x²+1) is a factor of 6x³y + 6xy − 12x² − 12
I think the answer to your question may be C.)
Answer:
y=1.1×10¹
Step-by-step explanation:
y=-4+15
y=11
y=1.1×10¹