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3 years ago

PLZZZZ HELPPPPPP MEEEEEE!!!!!! ASAP!!! ILL GIVE 20 POINTS AND BRAINLIEST!!!

Physics

1 answer:

Snowcat [4.5K]3 years ago

3 0

Answer:

the answers the correct one is C

Explanation:

In radioactive decay processes, a very important concept is the half-life time, which is the time it takes for the parent nuclei to decompose into child nuclei.

expressed this mathematically is

N = N₀ $e^{- \lambda t}$

for the average life time

N₀ / 2 = N₀ $e^{- \lambda T_{1/2}$

T = $\frac{ln 2x}{ \lambda}$

Analyzing this expression, the nuclei that decay are the so-called parents and the new nuclei called children appear.

when checking the answers the correct one is C

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A uniform solid disk of radius 1.60 m and mass 2.30 kg rolls without slipping to the bottom of an inclined plane. If the angular

bagirrra123 [75]

To solve this problem we will use the concepts related to energy conservation. Both potential energy, such as rotational and linear kinetic energy, must be conserved, and the gain in kinetic energy must be proportional to the loss in potential energy and vice versa. This is mathematically

$PE = KE_{lineal} + KE_{rotational}$

$mgh = \frac{1}{2}mv^2 +\frac{1}{2} I\omega^2$

Where,

m = mass

v = Tangential Velocity

$\omega$ = Angular velocity

I = Moment of Inertia

g = Gravity

Replacing the value of Inertia in a Disk and rearranging to find h, we have

$mgh = \frac{1}{2}mv^2 +\frac{1}{2} I\omega^2$

$mgh = \frac{1}{2}mr^2\omega^2 + \frac{1}{2}(\frac{1}{2}mr^2)\omega^2 )$

$h = \frac{3}{4} \frac{r^2\omega^2}{g}$

Replacing,

$h = \frac{3}{4} \frac{(1.6)^2 (5.35)^2}{9.8}$

$h = 5.607m$

Therefore the height of the inclined plane is 5.6m

3 0

4 years ago

A photoelectric experiment is performed where green light with a wavelength of 546.1 nm is shined on a metal plate, creating a p

PtichkaEL [24]

Answer:

$\phi=1.55 [eV]$

Explanation:

We can use the work function equation for a photoelectric experiment:

$\phi=\frac{hc}{\lambda}-K_{max}$

h is the plank constant
c is the speed of light
λ is the wave length
K is the kinetic energy (or K=eΔV)

So we will have:

$\phi=\frac{hc}{\lambda}-e\Delta V$

$\phi=\frac{6.63*10^{-34}*3*10^{8}}{546.1*10^{-9}}-0.728eV$

$\phi=3.64*10^{-19}[J]-0.728 [eV]$

$\phi=(3.64*10^{-19}[J]*\frac{1eV}{1.6*10^{-19}[J]})-0.728 [eV]$

$\phi=2.28 [eV] - 0.728 [eV]$

$\phi=1.55 [eV]$

I hope it helps you!

8 0

4 years ago

Read 2 more answers

The daily average insolation on the earth surface is approximately 6 kWh/m2 (ignoring cloudy weather). If a commercially availab

miv72 [106K]

Answer:

The area is 15.502 km².

The fraction is $\dfrac{31}{218500}$

Explanation:

Given that,

Daily average insolation = 6 kWh/m²

Efficiency = 20%

Population = 324 million

Per capita power = 1378 watts

Area of tennessee = 109250 km²

We need to calculate the daily power required

Using given data

$daily\ power=population\times Per\ capita\ power$

Put the value into the formula

$daily\ power = 324\times10^{6}\times1378$

$daily\ power=4.4647\times10^{11}\ watts$

$daily\ power=4.4647\times10^{8}\ kW$

We need to calculate the total energy per day

Using given data

$E=6\tiimes24$

$E=144\ kW/m^2$

We need to calculate the out of total energy

Using energy and efficiency

$E'=E\times\eta$

$E'=144\times\dfrac{20}{100}$

$E'= 28.8\ kW/m^2$

We need to calculate the area

Using formula of area

$A=\dfrac{daily\ power}{out\ of\ energy}$

Put the value into the formula

$A=\dfrac{4.4647\times10^{8}}{28.8}$

$A=15.502\ km^2$

We need to calculate the fraction of Tennessee that is required to power

Using given data

$fraction =\dfrac{Area}{tennessee}$

Put the value into the formula

$fraction =\dfrac{15.502}{109250}$

$fraction=\dfrac{31}{218500}$

Hence, The area is 15.502 km².

The fraction is $\dfrac{31}{218500}$

6 0

4 years ago

Define vector quantity giving examples

Mama L [17]

Answer:

Quantity with direction and magnitude

Displacement

Explanation:

6 0

3 years ago

A ladder 5.0 m long leans against a wall inside a spaceship. From the point of view of a person on the ship, the base of the lad

andriy [413]

Answer:

the angle the ladder makes with the floor as seen by an observer on Earth is 71.9°

Explanation:

Given the data in the question and as illustrated in the diagram below.

speed of the ship v = 0.90c

base of the ladder from the wall x₀ = 3.0 m

top of the later above the floor y = 4.0 m

we determine angle θ.

from the diagram,

tanθ = y/x₀

tanθ = y / x₀√( 1 - v²/c² )

we substitute

tanθ = 4.0 / 3.0√( 1 - ((0.9c)²/c²) )

tanθ = 4.0 / 3.0√( 1 - ((0.9²)c²/c²) )

tanθ = 4.0 / 3.0√( 1 - (0.9²) )

tanθ = 4.0 / 3.0√( 1 - 0.81 )

tanθ = 4.0 / 3.0√0.19

tanθ = 4.0 / 1.30766968

tanθ = 3.058876

θ = tan⁻¹( 3.058876 )

θ = 71.8965 ≈ 71.9°

Therefore, the angle the ladder makes with the floor as seen by an observer on Earth is 71.9°

3 0

3 years ago