All categories

3 years ago

Physics is explicitly involved in studying which of these activities?

1 answer:

5 0

Physics is explicitly involved in studying <span>the motion of a spacecraft under gravitational influence. Thus the answer is C.
Physic focuses more on the measurement, gravity, distances, acceleration and motion. THough all the choices are sciences but the C. is the topic that physics is involved.</span>

You might be interested in

Suppose a skydiver (mass =100kg) is falling towards the earth. When the skydiver is 80 m above the earth he is moving at 60 m/s

goblinko [34]

Answer:

The total mechanical energy of the skydiver is, E = 96402.6 J

Explanation:

Given data,

The mass of the skydiver, m = 100 kg

The speed of the skydiver at 80 m height, v = 60 m/s

The initial velocity of the skydiver, u = 0

Using the III equations of motion,

v² = u² + 2gs

s = v²/2g

Substituting the given values,

s = ½ 60²/ 9.8

= 18.37 m

Hence the initial total distance of the skydiver from the ground initially,

h = s + d

= 18.37 + 80

= 98.37 m

Since the total mechanical energy of a system is conserved, the total mechanical energy of the skydiver at height 'h' is equal to the total mechanical energy at height 'd'.

E = P.E + K.E

= mgh + ½ mu²

= 100 x 9.8 x 98.37 ( ∵ u = 0)

= 96402.6 J

Hence, the total mechanical energy of the skydiver is, E = 96402.6 J

5 0

3 years ago

What is the internal resistance of a 12.0 V car battery whose terminal voltage drops to 8.2 V when the starter draws 75 A

jonny [76]

Answer:

The internal resistance of the cell is 0.051 ohm.

Explanation:

Given;

emf of the battery, E = 12 V

terminal voltage of the cell, V = 8.2 V

current in the circuit, I = 75 A

let the potential drop of the cell due to internal resistance (r) = Ir

The internal resistance of the cell is calculated from the equation below;

E = V + Ir

where;

r is the internal resistance of the cell

$Ir = E - V\\\\r = \frac{E-V}{I} \\\\r = \frac{12-8.2}{75} \\\\r = 0.051 \ ohm$

Therefore, the internal resistance of the cell is 0.051 ohm.

6 0

3 years ago

The water behind Grand Coulee Dam is 1000 m wide and 200 m deep. Find the hydrostatic force on the back of the dam. (Hint: the t

Vika [28.1K]

Answer:

The hydro static force on the back of the dam is $1.96\times10^{11}\ N$

Explanation:

Given that,

Width b= 1000 m

Depth d= 200 m

We need to calculate the average pressure

Using formula of average pressure

$P_{avg}=\rho\times g\times d_{avg}$

Put the value into the formula

$P_{avg}=1000\times9.8\times100$

$P_{avg}=980000\ Pa$

We need to calculate the hydro static force on the back of the dam

Using formula of force

$F = P_{avg}\times A$

Put the value into the formula

$F = 980000\times1000\times200$

$F=1.96\times10^{11}\ N$

Hence, The hydro static force on the back of the dam is $1.96\times10^{11}\ N$

7 0

3 years ago

Radiation, conduction, and convection are methods of energy transfer. Of these methods, radiation is the only one in which energ

8_murik_8 [283]

C. Space.

Radiation is a process by which heat energy is transferred through space.

4 0

3 years ago

Read 2 more answers

Two objects of mass m move in opposite directions toward each other. The green object moves at velocity v, and the blue object m

NeX [460]

. The velocity of a mass attached to a spring is given by v = (1.5 cm/s) sin(ωt + π/2), ..... Which of the following is the motion of objects moving in two dimensions

5 0

4 years ago

Read 2 more answers