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nignag [31]
3 years ago
11

Difference between global warming and climate change

Physics
1 answer:
KIM [24]3 years ago
6 0

Answer:

Global warming refers only to the Earth’s rising surface temperature, while climate change includes warming and the “side effects”

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"Which of the following best describes the circuit shown below?
Anettt [7]
The figure shown above is series combination as the two resistors (bulb) are there which are then connected to the battery
so i conclude from the above options given the option  is B
hope it helps
3 0
3 years ago
Read 2 more answers
Physical data is often used in the court system. In fact, police officers use radar to determine your speed when you are driving
Mashcka [7]

The driver is telling the truth, the radar gun must have been set incorrectly to record relative velocity.

The given parameters:

  • <em>Speed of the driver observed by the stationary police officer, Vo = 44.7 m/s</em>
  • <em>Speed of the driver, V = 26.8 m/s.</em>
  • <em>Speed limit = 60 mph</em>

The speed limit of the driver in meter per second is calculated as follows;

= 60 \ \times \frac{miles}{hour} \times \frac{1609.34 \ m}{1 \ mile} \times \frac{1 \ hr}{3600 \ s}\\\\= 26.82 \ m/s

From the speed limit, it is obvious that the driver's speed is within the limit. Thus, we can conclude that the driver is telling the truth, the radar gun must have been set incorrectly to record relative velocity.

Learn more about relative velocity here: brainly.com/question/17228388

6 0
2 years ago
How do you express 78,000 in scientific notation?
White raven [17]
The Answer is= 7.8 x 10^4
7 0
3 years ago
Use your periodic table to answer the following question.
Pavel [41]
Helium has only 2 electrons in it's valence shell

So, option D is your answer.

Hope this helps!
6 0
3 years ago
The pressure P (in kilopascals), volume V (in liters), and temperature T (in kelvins) of a mole of an ideal gas are related by t
stich3 [128]

Answer:

\dfrac{dV}{dt} = -0.466 m^3/s

Explanation:

given,

P (in kilo pascals),         volume V (in liters),        temperature T (in kelvins)

P V = 8.31 T

Rate of increase the temperature =  0.1 K/s

temperature = 285 K

Pressure = 18 kPa

increasing at the rate of 0.07 k Pa/s

Rate at which volume is changing = ?

V = 8.31 \dfrac{T}{P}

\dfrac{dV}{dt} = 8.31 \dfrac{P\dfrac{dT}{dt}-T\dfrac{dP}{dt}}{P^2}

\dfrac{dV}{dt} = 8.31 \dfrac{18 \times 0.1-285\times 0.07}{18^2}

\dfrac{dV}{dt} = 8.31 \dfrac{-18.15}{324}

\dfrac{dV}{dt} = -0.466 m^3/s

7 0
3 years ago
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