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Sauron [17]
2 years ago
11

Pls help . (when u get in the document its duplicated)

Mathematics
2 answers:
Digiron [165]2 years ago
7 0
The picture isn’t there
riadik2000 [5.3K]2 years ago
6 0
The picture is not showing up
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Which is the volume of a cube if each side measures 1 foot
grandymaker [24]
<span>volume of a cube
V= a^3 = 1^3 = 1

answer

</span><span>D . 1 cubic foot</span>
4 0
3 years ago
Please help me I’m begging you please please please help me I need your help I’m begging you for your help please do me this fav
alisha [4.7K]

Hey there!

The first thing we can do is find the number of third in 4.

We can do this by multiplying 4 by 3 since there are 3 thirds in a whole.

4 x 3 = 12

So, 4 = 12/3

If she studies for 2/3 an hour each night, then we can divide 12 by 2 to figure out how many 2/3 go into 12/3.

12 ÷ 2 = 6

So, she studied for 6 days.

Hope this helps!

6 0
3 years ago
Answer pleaseee :)))
Mrac [35]

Answer:

m∠XYZ=106°, m∠XWY = 53°

Step-by-step explanation:

XYZ is a central angle, its arc is XY = 106°. so m∠XYZ = mXY=106°

XWY is an inscribed angle, its arc XY = 106°, so m∠XWY =1/2 mXY=1/2*106=

= 53°

4 0
4 years ago
Triangle UVW has a perimeter of 11.5 units. Solve for y.
vodomira [7]

Answer:

y = 3.2 units

Step-by-step explanation:

Find the missing angle measure x. Use the fact that all interior angle measures in a triangle add up to 180 degrees.

  • 55 + 50 + x = 180
  • 105 + x = 180
  • x = 75

We can use the Law of Cosines to determine the missing side length y.

  • a² = b² + c² - 2bc · cos(A)

Let's set UW (y) as a, WV as b, and UV as c. Therefore, ∠V must be A, ∠U must be B, and ∠W must be C.

Use the Law of Cosines to solve for a (side length y).

  • a² = b² + c² - 2bc · cos(A)
  • a² = (4)² + (3.5)² - 2(4)(3.5) · cos(50)
  • a² = 28.25 - 28cos(50)
  • a² =  28.25 - 17.99805307
  • a² = 10.25194693
  • a = 3.20186616366    

Side length y is equal to 3.2 units.

8 0
3 years ago
Seven runners, Allen, Beth, Calli, Drew, Erin, Fred, and Gary, are being timed running a mile. Only one runner can run at a time
amid [387]

Answer:

E. Beth Runs Second

Step-by-step explanation:

I will attempt to simplify this by ordering the list after each instruction.

Allen Runs First, Fred Fifth and Erin Seventh

1. Allen

2.

3.

4.

5. Fred

6.

7. Erin

Since Erin can only run directly before or after Drew if Allen runs first.

1. Allen

2.

3.

4.

5. Fred

6. Drew

7. Erin

If At least one person must run between Fred and Gary, Gary can either be in Position 2 or 3. Since Beth must run before Gary,

1. Allen

2. Beth

3. Gary

4. Calli

5. Fred

6. Drew

7. Erin

4 0
3 years ago
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