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3 years ago

Which table shows only values that represent the following relationship between q and r? r = q + 10.1

Mathematics

1 answer:

Allushta [10]3 years ago

6 0

Answer:

The answer is B

Step-by-step explanation:

This is because you need to add 10.1 to the variable "q"

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Consider the function y=0.88(1.1)x.identify what type of function this is

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Step-by-step explanation:

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Answer:

Step-by-step explanation:

as you see the smaller model is the same shape if you put the small model the same way the big one is you see the small model has a one where the big one has a nine so you times everything by nine because nine times one is 9 so you do that and see that the two is where the x is and times the 2 by nine and thats your answer

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3 years ago

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Which of the following is true about the sequence graphed below? (and Why)

WITCHER [35]

Answer:

Step-by-step explanation:

a₂ = 9

a₃ = a₂-1.5

a₄ = a₃-1.5

a₅ = a₄-1.5

etc.

The terms have a common difference of -1.5, so the sequence is arithmetic.

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3 years ago

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Suppose a random variable, x, arises from a binomial experiment. If n = 6, and p = 0.30, find the following probabilities using

AlladinOne [14]

Answer:

a) P(X=1) = 0.302526

b) P(X=5) = 0.010206

c) P(X=3) = 0.18522

d) P(X≤3) = 0.92953

e) P(X≥5) = 0.010935

f) P(X≤4) = 0.989065

Explanation:

Binomial experiments are modeled by the formula:

$P(X=x)=C(n,x)\cdot p^x\cdot (1-p)^{(n-x)}$

Where

P(X=x) is the probability of exactly x successes

$C(n,x)=\dfrac{n!}{x!\cdot (n-x)!}$

p is the probability of one success, which must be the same for every trial, and every trial must be independent of other trial.

n is the number of trials

1 - p is the probability of fail

there are only two possible outcomes for each trial: success or fail.

a.) P (x=1)

$P(X=1)=\dfrac{6!}{1!\cdot (6-1)!}\times (0.3)^1\times(1-0.3)^{(6-1)}=0.302526$

b.) P (x=5)

$P(X=5)=\dfrac{5!}{5!\cdot (6-5)!}\times (0.3)^5\times (1-0.3)^{(6-5)}=0.010206$

c.) P (x=3)

Using the same formula:

$P(X=3)=0.18522$

d.) P (x less than or equal to 3)

P(X≤3)= P(X=3) + P(X=2) + P(X=1) + P(X=0)

Also,

P(X≤3) = 1 - P(X≥4) = 1 - P(X=4) - P(X=5) - P(X=6)

You can use either of those approaches. The result is the same.

Using the second one:

P(X=4) = 0.059335
P(X=5) = 0.010206
P(X=6) = 0.000729

P(X≤3) = 1 - 0.05935 - 0.010206 - 0.000729 = 0.92953

e.) P(x greather than or equal to 5)

P(X≥5) = P(X=5) + P(X=6)

P(X≥5) = 0.010206 + 0.000729 = 0.010935

f.) P(x less than or equal 4)

P(X≤4) = 1 - P(X≥5) = 1 - P(X=5) - P(X=6)

P(X≤4) = 1 - 0.010206 - 0.000729 = 0.989065

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4 years ago

11. Use your ruler to measure in centimetres the lengths of the lines marked P, Q and R.

miv72 [106K]

Unfortunately we are unable to do this question since the question would have to be in the correct scale (meaning we need the original copy not a camera version). This question must be done by you. Just use a ruler and measure the lines

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3 years ago