![\displaystyle\lim_{h\to0}\frac{(5+h)^{-1}-5^{-1}}h=\lim_{h\to0}\frac{\frac5{5(5+h)}-\frac{5+h}{5(5+h)}}h](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Clim_%7Bh%5Cto0%7D%5Cfrac%7B%285%2Bh%29%5E%7B-1%7D-5%5E%7B-1%7D%7Dh%3D%5Clim_%7Bh%5Cto0%7D%5Cfrac%7B%5Cfrac5%7B5%285%2Bh%29%7D-%5Cfrac%7B5%2Bh%7D%7B5%285%2Bh%29%7D%7Dh)
![\displaystyle=-\lim_{h\to0}\frac h{5(5+h)h}](https://tex.z-dn.net/?f=%5Cdisplaystyle%3D-%5Clim_%7Bh%5Cto0%7D%5Cfrac%20h%7B5%285%2Bh%29h%7D)
![\displaystyle=-\lim_{h\to0}\frac1{5(5+h)}=-\frac1{25}](https://tex.z-dn.net/?f=%5Cdisplaystyle%3D-%5Clim_%7Bh%5Cto0%7D%5Cfrac1%7B5%285%2Bh%29%7D%3D-%5Cfrac1%7B25%7D)
Alternatively, recall that if
![f(x)=\dfrac1x](https://tex.z-dn.net/?f=f%28x%29%3D%5Cdfrac1x)
, then
![f'(x)=-\dfrac1{x^2}](https://tex.z-dn.net/?f=f%27%28x%29%3D-%5Cdfrac1%7Bx%5E2%7D)
, and so
![f'(5)=\displaystyle\lim_{x\to5}\frac{\frac1x-\frac15}{x-5}](https://tex.z-dn.net/?f=f%27%285%29%3D%5Cdisplaystyle%5Clim_%7Bx%5Cto5%7D%5Cfrac%7B%5Cfrac1x-%5Cfrac15%7D%7Bx-5%7D)
Take
![h=x-5](https://tex.z-dn.net/?f=h%3Dx-5)
, so that
![x=h+5](https://tex.z-dn.net/?f=x%3Dh%2B5)
, and we have the original limit. So the limit is equivalent to the value of
![f'(5)](https://tex.z-dn.net/?f=f%27%285%29)
, i.e.
Answer:
No, it is not a statistical question.
Step-by-step explanation:
In a human's teeth, there are 32 teeth.
Answer:
See below ~
Step-by-step explanation:
Anthony has graphed the inequality y ≤ -2x + 1.
For an inequality using a > or < sign, a <u>dotted line</u> has to be used instead of a solid line.
U gots do 19000 * 6%
0.06 eqs 6% bb
19000 * 0.06 es $<u>1140 a YEAR</u>
A=lb
a=100×40=4000cm^2
a=0.5×lb
a=0.5×40×30
a=600cm^2
a=4000+600
a=4600cm^2 hope it helps!!!!!!!!!!!!!!!!!!!!!!!!!!!