Question

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Answer 1

Answer:

Step-by-step explanation:

f(x) = (2x^2 + 1)

( f(3 + h) - f(3) ) / h

f(3 + h) = 2(3 + h)^2 + 1)

f(3 + h) = 2(9 + 6h + h^2) + 1

f(3 + h) = 18 + 12h + 2h^2 + 1

f(3 + h) = 19 + 12h +2h^2

f(3) = 2*(3^2) + 1

f(3) = 2(9) + 1

f(3) = 19

f(3 + h) - f(3) = 2h + 2h^2  The 19s cancel out

f(3 + h) - f(3) = 2h(1 +  h^2)

(  f(3 + h) + f(3)  ) / h  =  2h ( 1 + h^2) / h = 2 ( 1 + h^2)

Answer 2

Answer:

Step-by-step explanation: