Answer:
13, 14, 15
Step-by-step explanation:
Three consecutive integers have a sum of 42 means which 3 numbers in a row add up to 42
We can call the lowest integer x,
the next integer x+1 (since our integers need to be even)
the third integer x+2
algebraic equation: 42 = x + (x+1) + (x+2).
Combine like terms on the right side,
42 = 3x + 3
Subtract 3 from each side
39 = 3x
Divide each side by 3
x=13, which is our lowest integer.
The next two integers we find with 13 + 1 =.14 and 13 + 2 = 15
13 + 14 + 15 = 42.
Steps to solve:
2(n + 3) = 2n + 3
~Distribute left side
2n + 6 = 2n + 3
~Subtract 6 to both sides
2n = 2n - 3
~Subtract 2n to both sides
n = -3
Best of Luck!
9514 1404 393
Answer:

Step-by-step explanation:
The left section is defined at x = -5, but not at x = 0, so the interval for that definition is -5 ≤ x < 0. The function value on that interval is constant: 3.
The right section is defined a x = 5, but not at x = 0, so the interval for that definition is 0 < x ≤ 5. That section is a straight line with a slope of -1 and a y-intercept of 1. The function value on that interval can be written -x+1.
Then the piecewise definition is ...
f(x) = {3, for -5 ≤ x < 0; -x+1, for 0 < x ≤ 5}
Answer:
(2x + 3)(x - 7)
Step-by-step explanation: