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2 years ago

Rachel has $9 in a savings account. The interest rate is 5%, compounded annually.

1 answer:

7 0

1 % of 9 is 0.09, multiply 0.09 by 5= 0.45 (to find 5%)
Then multiply 0.45 by 36 (3years)= 16.20
Then add 16.20 to $9= $25.20

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How many Grams to 1 ounce?

polet [3.4K]

Answer:

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2 years ago

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Nana76 [90]

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3 years ago

Can I get help with this question?

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3 years ago

A baseball team has home games on Friday and Sunday. The two games together earn $3432.00 for the team. Friday's game generate

scoundrel [369]

Answer:

Friday's game generates $1,664 while Sunday's, game generates $1,768 for a total of $3432.00.

Step-by-step explanation:

First, identify what you know:

1) A baseball team has home games on Friday and Sunday

2) Both games, combined, earned $3432.00

3) Friday's game generated $104.00 less than Sunday's game.

We can create a formula to solve our problem!

$3,432 = x + (x - 104)

$3,432 + 104 = x + x

$3,536 = 2x

$3,536/2 = x

x = $1,768

Sunday's game earned $1,768! If Friday's game earned $104 less, then simply subtract that from Sunday's earning!

$1,768 - $104 = $1,664

Friday's game cost $1,664, and Sunday's game earned $1,768!

Hope this helps! :)

7 0

3 years ago

Read 2 more answers

One positive number is one-fifth of another number. the difference of the two numbers is 84. find the numbers.

seraphim [82]

Answer: The numbers are: " 21 " and " 105 " .
___________________________________________________
Explanation:
___________________________________________________
Let "x" be the "one positive number:

Let "y" be the "[an]othyer number".

x = 1/5 (y)
___________________________________________________
Given that the difference of the two number is "84" ; and that "x" is (1/5) of "y" ; we determine that "x" is smaller than "y".

So, y − x = 84 .

Add "x" to each side of this equation; to solve for "y" in terms of "x" ;

y − x + x = 84 + x ;

y = 84 + x ;
___________________________________________________
So, we have:

x = (1/5) y ;

and: y = 84 + x ;

Substitute "(1/5)y" for "x" ; in "y = 84 + x " ; to solve for "y" ;

y = 84 + [ (1/5)y ]

Subtract " [ (1/5)y ] " from EACH SIDE of the equation ;

y − [ (1/5)y ] = 84 + [ (1/5)y ] −  [ (1/5)y ] ;

to get:

[ (4/5)y ] = 84 ;

       ↔    (4y) / 5 = 84 ;

        → 4y = 5 * 84 ;

      Divide EACH SIDE of the equation by "4" ;
to isolate "y" on one side of the equation; and to solve for "y" ;

           4y / 4 = (5 * 84) / 4 ;

                 y = 5 * (84/4) = 5 * 21 = 105 .

   y = 105 .
___________________________________________________
Now, plug "105" for "y" into:
___________________________________________________
Either:
___________________________________________________
x = (1/5) y ;

OR:

y = 84 + x ;
___________________________________________________
to solve for "x" ;
___________________________________________________
Let us do so in BOTH equations; to see if we get the same value for "x" ; which is a method to "double check" our answer ;
___________________________________________________
Start with:

x = (1/5)y

    → (1/5)*(105) = 105 / 5 = 21 ; x = 21 ;

___________________________________________________
So, x = 21; y = 105 .
___________________________________________________
Now, let us see if this values hold true in the other equation:
___________________________________________________
y = 84 + x ;

105 = ? 84 + 21 ?

105 = ? 105 ? Yes!
___________________________________________________
The numbers are: " 21 " and "105 " .
___________________________________________________

6 0

3 years ago