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3 years ago

The graph of a proportional relationship passes through (6, 42)(6, 42) and (1, y)(1, y). Find y.

Mathematics

1 answer:

n200080 [17]3 years ago

5 0

Answer:

y=7

Step-by-step explanation:

6/42 =1/y

y=42/6=7

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On a separate sheet of paper, graph the function. In the answer box, describe the function.

Mumz [18]

Answer:

Step-by-step explanation:

Given piecewise function is,

f(x) = -5x + 2 If x < 2

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3 years ago

A candy company has 150 kg of chocolate-covered nuts and 90 kg of chocolate-covered raisins to be sold as two different mixes. O

Westkost [7]

Answer:

1. 7x + 9.5y

2. 1980

Step-by-step explanation:

In Mix A, there is an equal amount of nuts and raisins.

Let x = kg of nuts = kg of raisins.

In Mix B, there is 3 times as much nuts as raisins.

Let y = kg of raisins, then 3y = kg of nuts.

We have this information:

Nuts Raisins Price

mix A x + x = $ 7.00

mix B 3y + y = $ 9.50

Total: 150 90

Hence, the number of kilograms of each mix should company prepare for the maximum revenue is = 7x + 9.5y

We have these inequalties:

{x≥0y≥0x+3y≤150x+y≤90} (equation 1)

There will be

x+x=2x kg of Mix A at $7.00 per kg.

The revenue from Mix A is:

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There will be

3y+y=4y kg of Mix B at $9.50 per kg.

The revnue from Mix B is:

9.5(4y)=38y dollars.

Hence, the total revenue is:

R=14x+38y (equation 2).

Graph the region determined by [1] and locate its vertices.

You should get:

(0,0),(90,0),(0,50),(60,30)

Test the vertices into [2] and see which vertex produces maximum revenue

(0,0): R=14(0)+38(0)=0 Minimum revenue

(90,0):R=14(90)+38(0)=1260

(0,50): R=14(0)+38(50)=1900

(60,30):R=14(60)+38(30)=1980 Maximum revenue.

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