Write an equation to represent each graph

What is the best estimate for the value of the expression?

harkovskaia [24]

Answer: 8 is the anwser

Step-by-step explanation:

7 0

3 years ago

Ryan counts 505,515, 525, 535, 545, 555. By which number does Ryan skip count?

raketka [301]

The Anwser would se 7,363

5 0

2 years ago

How do I solve this??

Strike441 [17]

Answer:

r = -1/2

Step-by-step explanation:

3(5 + 4r) = -18r

15 +12r = -18r by distributive property

15 = -12r - 18r

15 = -30r

r = - 1/2r

4 0

2 years ago

Read 2 more answers

ASAP HELP HELP NEED HELP FAILING

frez [133]

For the first question, you will write a ratio of 1/2 oz:10 pounds. Please see the attached picture. There are 9 groups of 10 oz in 90 oz, so you will need 9 groups of the amount of medicine too!

For the second question, you need to understand that the exponent (2^3) must be evaluated first because all forms of multiplication/ groupings comes first before adding or subtracting.
Exponents are a way of showing repeated multiplication, so it is done first.

3 0

2 years ago

Dual-energy X-ray absorptiometry (DXA) is a technique for measuring bone health. One of the most common measures is total body b

kramer

Answer:

(a)

$\bar x = 0.0075$

$s = 0.0049$

(b)

B. The sample is too small to make judgments about skewness or symmetry.

Step-by-step explanation:

Given:

$n = 8$

$\begin{array}{ccccccccc}{} & {S} & {u} & {b} &{j} & {e} & {c} & {t} & {s} &{Operator} & {1} & {2} & {3} & {4} & {5} & {6} & {7} & {8} & {1} & 1.326 & 1.337 & 1.079 & 1.229 & 0.936 & 1.009 & 1.179 & 1.289 & 2 & 1.323 & 1.322 & 1.073 & 1.233 & 0.934 & 1.019 & 1.184 & 1.304 \ \end{array}$

Solving (a):

First, calculate the difference between the recorded TBBMC for both operators:

$\begin{array}{ccccccccc}{} & {S} & {u} & {b} &{j} & {e} & {c} & {t} & {s} &{Operator} & {1} & {2} & {3} & {4} & {5} & {6} & {7} & {8} & {1} & 1.326 & 1.337 & 1.079 & 1.229 & 0.936 & 1.009 & 1.179 & 1.289 & 2 & 1.323 & 1.322 & 1.073 & 1.233 & 0.934 & 1.019 & 1.184 & 1.304 &{|1 - 2|} &0.003 & 0.015 & 0.006 & 0.004 & 0.002 & 0.010 & 0.005 & 0.015 \ \end{array}$

The last row which represents the difference between 1 and 2 is calculated using absolute values. So, no negative entry is recorded.

The mean is then calculated as:

$\bar x = \frac{\sum x}{n}$

$\bar x = \frac{0.003 + 0.015 + 0.006 + 0.004 + 0.002 + 0.010 + 0.005 + 0.015}{8}$

$\bar x = \frac{0.06}{8}$

$\bar x = 0.0075$

Next, calculate the standard deviation (s).

This is calculated using:

$s = \sqrt{\frac{\sum (x - \bar x)^2}{n}}$

So, we have

$s = \sqrt\frac{(0.003 - 0.0075)^2 + (0.015 - 0.0075)^2+ (0.006- 0.0075)^2+ ....... + (0.005- 0.0075)^2+ (0.015- 0.0075)^2 }{8}$ $s = \sqrt\frac{0.00019}{8}$

$s = \sqrt{0.00002375$

$s = 0.0049$

Solving (b):

Of the given options (A - E), option B is correct because the sample is actually too small

6 0

2 years ago

Write an equation to represent each graph​

Write an equation to represent each graph