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Umnica [9.8K]
3 years ago
10

PLEASE HELP I WILL GIVE 50 POINTS! IF YOU GIVE FAKE ANSWER I WILL REPORT YOU!!!

Mathematics
1 answer:
defon3 years ago
3 0

Answer:

It looks like your first account increases linearly,

unless you have a typo and meant:

f(x) = 10,125(1.83)^x

the second  

exponential and can be written as

g(r) = 9,638(1.95)^r

clearly g(r) has a higher percentage change since 1.95 > 1.83

a more interesting question might have been: When will the amount be the same?

10,125(1.83)^x = 9,638(1.95)^x

10,125(1.83)^x = 9,638(1.95)^x

(1.83)^x = .951901...(1.95)^x

take log of both sides and use log rules

xlog1.83 = log .951901... + log 1.95

x(log 1.83 - log 1.95) = log .951901...

x = .776..

check:

f(.776..) = 10,125(1.83)^.776.. = 1618410

g(.776..) = 9,638(1.95)^.776... = 16184.10

Step-by-step explanation:

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