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2 years ago

Solve for x in the diagram below. x 2x (x+10)

Mathematics

2 answers:

horsena [70]2 years ago

8 0

Answer:

$x^{2} +10x^{3}$

Step-by-step explanation:

$x^{2} x(x+10)\\x^{4}+10x^{3}$

Firdavs [7]2 years ago

7 0

The square mark indicates that it is a right angle which is 90 degrees.
x+2x+x+10=90
4x+10=90
-10 -10
4x=80
Divide both sides by 4
x= 20

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Answer:

A. 4".

B. Approximately 9.54".

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Step-by-step explanation:

Please find the attachment.

Let x be the distance from the peak of the kite to the intersection of the diagonals and y be the distance from the peak of the kite to the intersection of the diagonals.

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We can see from our attachment that point O is the intersection of both diagonals. In triangle AOD the side length AD will be hypotenuse and side length DO will be one leg.

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Upon taking square root of both sides of our equation we will get,

$x=\sqrt{16}$

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Since distance can not be negative, therefore, the distance from the peak of the kite to the intersection of the diagonals is 4 inches.

B. We can see from our attachment that point O is the intersection of both diagonals. In triangle DOC the side length DC will be hypotenuse and side length DO will be one leg.

We can find the value of y using Pythagorean theorem as:

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Upon taking square root of both sides of our equation we will get,

$y=\sqrt{91}$

$y\pm 9.539392$

$y\pm\approx 9.54$

Since distance can not be negative, therefore, the distance from intersection of the diagonals to the top of the tail is approximately 9.54 inches.

C. We can see from our diagram that the length of longer diagram will be the sum of x and y.

$\text{The length of the longer diagonal}=x+y$

$\text{The length of the longer diagonal}=4+9.54$

$\text{The length of the longer diagonal}=13.54$

Therefore, the length of longer diagonal is approximately 13.54 inches.

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