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bearhunter [10]

3 years ago

15

Rate of change of d=60h + 20

1 answer:

77julia77 [94]3 years ago

6 0

H=1/3+1/60d,d=R Hope this is correct.

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|y| x-3 <br> what is the vertex

lutik1710 [3]

Answer:

(3,0)

Step-by-step explanation:

put x-3=0 and solve for it whic hwould be x=3

8 0

3 years ago

Find the solution of the given initial value problem in explicit form. y′=(1−5x)y2, y(0)=−12 Enclose numerators and denominators

Nata [24]

Answer:

The solution is $y=-\frac{12}{12x-30x^2+1}$ .

Step-by-step explanation:

A first order differential equation $y'=f(x,y)$ is called a separable equation if the function $f(x,y)$ can be factored into the product of two functions of $x$ and $y$ :

$f(x,y)=p(x)h(y)$

where $p(x)$ and $h(y)$ are continuous functions.

We have the following differential equation

$y'=(1-5x)y^2, \quad y(0)=-12$

In the given case $p(x)=1-5x$ and $h(y)=y^2$ .

We divide the equation by $h(y)$ and move $dx$ to the right side:

$\frac{1}{y^2}dy\:=(1-5x)dx$

Next, integrate both sides:

$\int \frac{1}{y^2}dy\:=\int(1-5x)dx\\\\-\frac{1}{y}=x-\frac{5x^2}{2}+C$

Now, we solve for $y$

$-\frac{1}{y}=x-\frac{5x^2}{2}+C\\-\frac{1}{y}\cdot \:2y=x\cdot \:2y-\frac{5x^2}{2}\cdot \:2y+C\cdot \:2y\\-2=2yx-5yx^2+2Cy\\y\left(2x-5x^2+2C\right)=-2\\\\y=-\frac{2}{2x-5x^2+2C}$

We use the initial condition $y(0)=-12$ to find the value of C.

$-12=-\frac{2}{2\left(0\right)-5\left(0\right)^2+2C}\\-12=-\frac{1}{c}\\c=\frac{1}{12}$

Therefore,

$y=-\frac{2}{2x-5x^2+2(\frac{1}{12})}\\y=-\frac{12}{12x-30x^2+1}$

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3 years ago

21 help asap Brailiest pic below

Dominik [7]

Answer:

A

Step-by-step explanation:

The inverse is just the opposite it is a flip

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3 years ago

What is the measure of the angle formed by the minute hand and hour hand of a clock in each case?

pentagon [3]

180°

120°

90°

hope this helps

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3 years ago

Friend me right quick pls

valina [46]

Answer:

ok ok ok i gotchuu

Step-by-step explanation:

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