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Marysya12 [62]
2 years ago
7

Hi, Please help me with this question, I'm not about my answer

Mathematics
2 answers:
sveta [45]2 years ago
8 0
X- axis goldfish
Y- axis coast
(20,30) 20 goldfish coast $30 dollars
vitfil [10]2 years ago
4 0
X- axis goldfish
y- axis cost
(20,30) 20 goldfish cost $30
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Today everything in a store is for sale. THe store offers a 30% discount. The regualar price for a T-shirt is 18$. What is the d
Serggg [28]

Answer:

12.60

Step-by-step explanation:

Start off by the total which is 18. To find the percentage off you will have to make the 30% into a decimal, so simply move it two spaces to the left. Now you have .30. Multiply the decimal, .30, and the full amount, 18. Your equation now should be (.30)*(18). Your answer will be 5.40. 5.40 is what is off of the shirt from the original price, so subtract 5.40 from 18. Your equation now is (18-5.40) which is 12.60.

7 0
3 years ago
(5 •10^16) • (2.8 • 10^-7)
Gelneren [198K]
That's 7/3 =2.3333333
7 0
2 years ago
7. 3.278 × 0.145
crimeas [40]

Answer:

7. 0.47531

8. 98.7252

9. 13238.984

10. 0.00757576

11. 15011.4286

12. Proper

13. Improper

14. 11/4

15. 33/7

16. 1 4/8 or 1 1/2

17. 3 1/6

Step-by-step explanation:

8 0
2 years ago
Write this in your own words
joja [24]
Are you talking about Halloween?

NVM can you delete that?I didn't read the begining
5 0
2 years ago
Find the distance, in feet, a particle travels in its first 2 seconds of travel, if it moves according to the velocity equation
just olya [345]

Answer:

The particle will travel 6 feet in first 2 seconds.

Step-by-step explanation:

We have been given that a particle moves according to the velocity equation v(t)= 6t^2-18t+12. We are asked to find the distance that the particle will travel in its first 2 seconds.

s(t)=\int |v(t)|dt

s(t)=\int\limits^2_0 |6t^2-18t+12|dt

Now, we will eliminate the absolute value sign as:

s(t)=\int\limits^1_0 6t^2-18t+12dt+\int\limits^2_1 -6t^2+18t-12dt

s(t)=[\frac{6t^3}{3}-\frac{18t^2}{2}+12t]^1_0 +[\frac{-6t^3}{3}+\frac{18t^2}{2}-12t]^2_1

s(t)=[2t^3-9t^2+12t]^1_0 +[-2t^3+9t^2-12t]^2_1

s(2)=2(1)^3-9(1)^2+12(1)-(2(0)^3-9(0)^2+12(0))-2(2)^3+9(2)^2-12(2)-(-2(1)^3+9(1)^2-12(1))

s(2)=2-9+12-(0)-16+36-24-(-2+9-12)

s(2)=5-(0)-4-(-5)

s(2)=5-4+5

s(2)=6

Therefore, the particle will travel 6 feet in first 2 seconds.

   

 

7 0
3 years ago
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