
The surface of interest can be parameterized by

with

and

.
The area of the surface

is given by the surface integral
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We have

so the area is given by the double integral
Look at the picture.
Use the Pythagorean theorem.

The diameter d = 2r.
Therefore
Answer: 45.5
Answer:
80
Step-by-step explanation:
The three angles of a triangle add to 180 degrees. One angle is 10, the second is a right angle( which is 90 degrees). Let the third angle be x
10 +90 +x = 180
Combine like terms
100 +x =180
Subtract 100 from each side
100-100 +x= 180-100
x = 80
The answer would be, A) +$2 because he spend $12 but earned $14 so when you subtract 14 and 12 you get $2, which would be his profit
M8 =43.
Reason:
134+ M8 =180(degrees). This is because angles on a straight line =180 (degrees)
180-134=M8
Therefore:
M<8 =180-134= 43 (degrees)
Hope this helps and makes sense.
Please mark as a brainliest (crowns)