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2 years ago

13

What is the maximum value of f(x)=−4x2+4x−2?

1 answer:

horrorfan [7]2 years ago

5 0

Answer: -1

Step-by-step explanation: A typical quadratic equation is $ax^{2} +bx+c$ and the maximum value formula is -b/2a, so let plug it in -4/2(-4) which equals 1/2. Then let plug 1/2 into the equation,

-4(1/2)^2+4(1/2)-2=

-1+2-2=

-1

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Find the solutions of the quadratic equation -9c² +2 +3 = 0.

Tresset [83]

Given that,

An equation : -9c² +2c +3 = 0

To find,

Find the value of x.

Solution,

We have, -9c² +2c +3 = 0

We can solve it using the formula as follows :

$x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}$

Here, a = -9, b = 2 and c =3

Put the values,

$c=\dfrac{-2\pm \sqrt{(2)^2-4(-9)(3)}}{2(-9)}\\\\c=\dfrac{-2+\sqrt{(2)^{2}-4(-9)(3)}}{2(-9)}, \dfrac{-2-\sqrt{(2)^{2}-4(-9)(3)}}{2(-9)}\\\\c=-0.47, 0.69$

So, the solution are -0.47 and 0.69.

8 0

3 years ago

Phantasy [73]

I believe the SSS theorem as they both share/have side measurements (and no defined angles)

6 0

2 years ago

What is the correct equation to solve for X?

Vanyuwa [196]

It’s the second option
sin(45)=13/x

6 0

2 years ago

Please help, thanks.

Liula [17]

Answer:

$\frac{ - 5}{54} + \frac{5 \times 6}{9 \times 6} = \frac{ - 5 + 30}{54} = \frac{25}{54}$

$\frac{15}{4} \div \frac{3}{8} = \frac{15}{4} \times \frac{8}{3} = 10$

$10 \times \frac{25}{54} = \frac{250}{54} = 4 \times \frac{17}{27}$

b )

$4 \times \frac{17}{27} = \frac{125}{27} =$

cube root =

$\frac{5}{3}$

c ) square root

$\frac{125}{27} = \frac{ \sqrt{25 \times 5} }{ \sqrt{3 \times 9} } = \frac{5 \sqrt{5} }{3 \sqrt{3} }$

3 0

3 years ago

Simplify the expression.

bagirrra123 [75]

Answer:

Step-by-step explanation:

Exponent rule:

$\boxed{(a^{m})^{n}=a^{m*n}}$

$(x^{\frac{2}{5}})^{10} = x^{\frac{2}{5}*10} \\\\\\$

$=x^{2*2}\\\\=x^{4}$

3 0

2 years ago