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2 years ago

13

What is the maximum value of f(x)=−4x2+4x−2?

1 answer:

horrorfan [7]2 years ago

5 0

Answer: -1

Step-by-step explanation: A typical quadratic equation is $ax^{2} +bx+c$ and the maximum value formula is -b/2a, so let plug it in -4/2(-4) which equals 1/2. Then let plug 1/2 into the equation,

-4(1/2)^2+4(1/2)-2=

-1+2-2=

-1

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Solve the equation<br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7Bx%20-%206%7D%20%20%2B%202%20%3D%206" id="TexFormula1" title

tensa zangetsu [6.8K]

Explanation:

First you had to square from both sides of equation form.

$(\sqrt{x-6+2})^2=6^2$

Then you expanded form.

$(\sqrt{x-6+2})^2=x-4$

$x-4=36$

$6^2=6*6=36$

Solve by equation form.

$x-4=36$

Add by four from both sides of equation form.

$x-4+4=36+4$

Simplify.

$x=40$

Verified solutions.

$x=40 \boxed{TRUE}$

Final answer: $\boxed{x=40}$

Hope this helps!

And thank you for posting your question at here on brainly, and have a great day.

-Charlie

7 0

2 years ago

Select the items the crusaders brought back with them from the East.

gulaghasi [49]

Answer:Jewels, WOOL, SILK

Step-by-step explanation:

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4 0

3 years ago

Read 2 more answers

A school is planning to construct two rectangular play areas in the playground. The length of play area A must be 1 foot longer

Anna11 [10]

Answer:

А.The system has two solutions, but only one is viable because the other results in a negative width.

Step-by-step explanation:

Given

Let:

$L_A \to$ length of play area A

$W_A \to$ width of play area A

$L_B \to$ length of play area B

$W_B \to$ width of play area B

$x \to$ Area of A

$y \to$ Area of B

From the question, we have the following:

$L_A = 1 + 4W_A$

$W_B = 2 + W_A$

$L_B = 2 + 3W_B$

$x = y$

The area of A is:

$x = L_A * W_A$

This gives:

$x = (1 + 4W_A) * W_A$

Open bracket

$x = W_A + 4W_A^2$

The area of B is:

$y = L_B * W_B$

$y = (2 + 3W_B) * ( 2 + W_A)$

Substitute: $W_B = 2 + W_A$

$y = (2 + 3(2 + W_A)) * ( 2 + W_A)$

Open brackets

$y = (2 + 6 + 3W_A) * ( 2 + W_A)$

$y = (8 + 3W_A) * ( 2 + W_A)$

Expand

$y = 16 + 8W_A + 6W_A + 3W_A^2$

$y = 16 + 14W_A + 3W_A^2$

We have that:

$x = y$

This gives:

$W_A + 4W_A^2 = 16 + 14W_A + 3W_A^2$

Collect like terms

$4W_A^2 - 3W_A^2 + W_A -14W_A - 16 =0$

$W_A^2 -13W_A - 16 =0$

Using quadratic calculator, we have:

$W_A = -14.1$ or $W = 1.13$ --- approximated

But the width can not be negative; So:

$W = 1.19$

7 0

2 years ago

The area of a parallelogram is 125 square inches and the height of the parallelogram is 10 inches. What is the lenght of the bas

kipiarov [429]

Answer:

12.5 inches is the correct answer.

Step-by-step explanation:

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6 0

3 years ago

3(5 - 2x) + 2(x-3) plz help me quick:(

trasher [3.6K]

Answer:

9-4x is simplified

Step-by-step explanation:

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7 0

3 years ago

Read 2 more answers