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Dafna1 [17]
3 years ago
15

Please please help me

Mathematics
2 answers:
Alinara [238K]3 years ago
7 0

Answer:

Step-by-step explanation:

using pythagoras theorem

a^2 + b^2 = c^2

here 4 and 9 are the legs of the right angled triangle so let them be a and b respectively . third side is the hypotenuse because it is opposite to 90 degree so let it be c.

4^2 + 9^2 = c^2

16 + 81 = c^2

97 = c^2

\sqrt{97} = c

nata0808 [166]3 years ago
6 0

Answer:

22is the answer cuz it is

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Ron Finley is a gardener who decided a few years ago to plant several gardens in South Central Los Angeles. He wants his next ga
yaroslaw [1]

Well, we can be sure that whatever the width is, we can call it ' W '. Then, from information in the question, the length of the garden is ' 3W '.

Now, the perimeter of a rectangle is (length + width + length + width). Using the fancy algebra labels I just gave them, that's (3W + W + 3W + W). And now I can go through that, add up all the Ws, and get a total of 8W for the perimeter.

But he question tells us that the perimeter is 24 yards, so 8W = 24 yds.

Divide each side of that equation by 8, and we discover that W = 3 yds. And if THAT's true, then 3W = 9 yds. Bada bing ! We have the dimensions of the garden.

It's 3 yards wide and 9 yards long.

3 0
4 years ago
What is -2/9(2x-9) help plz
garri49 [273]

Answer:

4

Step-by-step explanation:

-2/9(2×-9)

-2/9(-18)

(-2×-18)/9

-2×-2

4

3 0
3 years ago
What are the domain, range, and asymptote of h(x) = (0.5)x - 9
svetlana [45]

Answer:

The domain of h(x) is {x : x ∈ R}

The range of the function is {y : y > -9}

The horizontal asymptote is at y = -9

Step-by-step explanation:

* Lets read the problem and solve it

- The exponential function is f(x) = a(b)^x, where a and b are constant

  and b is the base , x is the exponent , a is the initial value of f(x)

- The domain of the function is all the values of x which make the

  function defined

- The range of the function is the set of values of y that corresponding

  with the domain x

- Asymptote on the graph a line which is approached by a curve but

 never reached

- A function of the form f(x) = a(b^x) + c always has a horizontal

 asymptote at y = c

* Lets solve the problem

∵ h(x) = (0.5)^x - 9

∵ All the values of x make h(x) defined

∵ The domain of the function is the values of x

∴ The domain of h(x) is {x : x ∈ R} ⇒ R is the set of real number

∵ The range of the function is the set of values of y which

   corresponding to x

∵ (0.5)^x must be positive because there is no values of x make it

  negative value

∴ y must be greater than -9

∴ The range of the function is {y : y > -9}

∵ A function of the form f(x) = a (bx) + c always has a horizontal

   asymptote at y = c

∵ h(x) = (0.5)^x - 9

∴ c = -9

∴ The horizontal asymptote is at y = -9

* Look to the attached file for more understanding

3 0
4 years ago
Read 2 more answers
Write an equation of the perpendicular bisector of the segment with endpoints M(10,-7) and N(-4,1).​
marin [14]
(Step#1): Find the Perpendicular bisector of a line segment with endpoints

(Step#2): Find a Point on the perpendicular bisector
(Which is the midpoint of a given line segment)
Using the midpoint Formula which is:
(X3, Y3) = (X1 +X22, Y1 + Y22)

I Hope this helps you!!!
6 0
3 years ago
4)
liberstina [14]
Arc length is the angle/360 times circumference. The diameter of the unit circle is 2. So the circumference of the unit circle is 2pi, if you use 3.14 for pi, then the circumference is 6.28. So your equation is
x/360 times 6.28=4.2, divide by 6.28, then multiply by 360
x=240.76432
Your answer rounded to the nearest thousanth is 240.764

6 0
3 years ago
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