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2 years ago

Which function is the result of translating f(x)=x^2+14 to the right 5 units and down 6 units

Mathematics

1 answer:

jeka942 years ago

6 0

Answer: F(x)= (x^2 -5) -8

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which of these numbers can be classifies as irrational 1/3 ,square root of 16, 0.73737373... or 0.87546201023....? will give bra

Verdich [7]

The .87546201023 because it is infinite and a fraction cant be written.
where as .73 can just be put over 99

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2 years ago

Pls help urgently extra points and mark brainlist

tankabanditka [31]

Answer:

(3+2)×5= 5 power 2

5 power 3= 125

10 power 2 over 2= 50

Step-by-step explanation:

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2 years ago

Who's good at Algebra? I have a few Questions about somethings on my home work.....

Rufina [12.5K]

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3 years ago

Read 2 more answers

Figure 1 and figure 2 are two congruent parallelograms drawn on a coordinate grid as shown below:

LenKa [72]

Answer:

(a) Reflection across the y-axis, followed by translation 10 units down

Step-by-step explanation:

Figure 2 is not a reflection across the origin of Figure 1, so neither of the double reflections will map one to the other.

Reflection across the y-axis will put the bottom point at (5, 3). The bottom point on Figure 2 is at (5, -7), so has been translated down by 3-(-7) = 10 units.

Figure 1 is mapped to Figure 2 by reflection over the y-axis and translation down 10 units.

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2 years ago

The 1992 world speed record for a bicycle (human-powered vehicle) was set by Chris Huber. His time through the measured 200 m st

Reil [10]

Answer:

a) 30.726m/s and b) 5.5549s

Step-by-step explanation:

a.) What was Chris Huber’s speed in meters per second(m/s)?

Given the distance and time, the formula to obtain the speed is

$v=\frac{d}{t}$ .

Applying this to our problem we have that

$v=\frac{200m}{6.509s}= 30.726m/s$ .

So, Chris Huber’s speed in meters per second(m/s) was 30.726m/s.

b) What was Whittingham’s time through the 200 m?

In a) we stated that $v=\frac{d}{t}$ . This formula implies that

$t=\frac{d}{v}$ .

First, observer that $19\frac{km}{h} =19,000\frac{m}{h}=\frac{19,000}{3,600}m/s= 5.2777m/s$ .

Then, Sam Whittingham speed was equal to Chris Huber’s speed plus 5.2777 m/s. So, $v=30.726\frac{m}{s} +5.2777\frac{m}{s}= 36.003 m/s.$

Then, applying 1) we have that

$t=\frac{200m}{36.003m/s}=5.5549s.$

So, Sam Whittingham’s time through the 200 m was 5.5549s.

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3 years ago