Answer:
7x
Step-by-step explanation:
It equals 28 just like the problem with parentheses, 7x .
Answer:
Yes
Step-by-step explanation:
A for loop basically relies on repeating the same code for a pre-set number of times. During which you can make any code repeat inside of it, including indexing through a type of list. Many times a for-loop will use the indexes in a list to calculate the number of times that the loop has to repeat. This is usually done in order to search or apply changes in an array of other types of data structures that have countless values stored in it.
Answer: ![\dfrac{4}{5}\ \text{ounces}\ \text{or}\ 0.8\ \text{ounces}](https://tex.z-dn.net/?f=%5Cdfrac%7B4%7D%7B5%7D%5C%20%5Ctext%7Bounces%7D%5C%20%5Ctext%7Bor%7D%5C%200.8%5C%20%5Ctext%7Bounces%7D)
Step-by-step explanation:
Given
There is 4 fluid ounces of red paint which needs to be shared among 5 students
So, division operation is needed to deduce the ounces of red paint each student will get
Each student get
![\Rightarrow \dfrac{4}{5}\ \text{ounces}\ \text{or}\ 0.8\ \text{ounces}](https://tex.z-dn.net/?f=%5CRightarrow%20%5Cdfrac%7B4%7D%7B5%7D%5C%20%5Ctext%7Bounces%7D%5C%20%5Ctext%7Bor%7D%5C%200.8%5C%20%5Ctext%7Bounces%7D)
<h3>
Answer: y = 2*cos(3pi*x) + 5</h3>
======================================
The general template for cosine is
y = A*cos(B(x-C)) + D
where,
|A| = amplitude
B = 2pi/T, with T being the period and T = 1/f, f is the frequency
C = determines horizontal phase shift
D = determines vertical shift, and is midline
---------------
In this case,
midline = 5 means D = 5
amplitude = 2 means A = 2
frequency = 3/2 means the period is T = 2/3, which is the reciprocal of the frequency, so B = 2pi/T = 2pi/(2/3) = 3pi
There is no mention of a phase shift, so C = 0.
---------------
All together we have
A = 2, B = 3pi, C = 0, D = 5
So,
y = A*cos(B(x-C)) + D
y = 2*cos(3pi(x-0)) + 5
y = 2*cos(3pi*x) + 5