Without rounding, I make it six. You could do it this way
54527/5^6 comes to a little over 3. That should be close enough. I'm going to check this by doing the divisions. I could let the computer do it, but I'd like to see if there's a pattern. There isn't and the correct answer is
6 <<<< divisions.
Answer:
not sure if its a song or not but you do you, gg <3
Answer:
$30.50
Step-by-step explanation:
b = bagels
c = cream cheese
<u>Given</u>
b = 30
c = 2
<u>Work:</u>
0.85b+2.5c
0.85(30) + 2.5(2)
25.5 + 5
30.5
Answer:
B
Step-by-step explanation:
Data set D does not contain the value 128, which is the median value.
Data set C does not contain the outlier value 91.
Data set A contains value 168, which does not show up on the plot.
The only remaining choice is B.
_____
In order, the data values of set B are ...
... 91, 114, 120, 126, 128, 128 134, 136, 139, 142, 152
The median value of these 11 is the 6th one: 128. The median values of the remaining two sets of 5 are 120 and 139, making these values the quartiles at the ends of the box. The value 91 is more than 1.5 times the IQR (19) below the 1st quartile, so is considered an outlier. (The cutoff is 120-1.5·19=91.5.)
Answer:
The correct option is B.
Step-by-step explanation:
The given function is
The translation of a function is defined as
If a>0, then the graph of f(x) shift a units left and if a<0, then the graph of f(x) shift a units right.
If b>0, then the graph of f(x) shift b units up and if b<0, then the graph of f(x) shift b units down.
It is given that the graph of f(x) shifts 4 units left and 2 units down. So, a=4 and b=-2.
![[\because f(x)=x^3]](https://tex.z-dn.net/?f=%5B%5Cbecause%20f%28x%29%3Dx%5E3%5D)
Therefore option B is correct.
