Which of the following describes a similarity between a solid and a gas

Mathematics

1 answer:

lyudmila [28]3 years ago

4 0

Answer:

they are both states of matter
they are both made up of atoms, molecules and ions
they both have volume

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You have 10 tbsp of onion powder.

evablogger [386]

Answer:

we can make 5 servings of spice rub from 10 table spoons of onion powder

Step-by-step explanation:

Given the data in the question;

2 table spoon of onion powder makes one serving of spice rub.

Total table spoons of onion powder available = 10

So Let x represent the number of servings of spice rub we can make from our 10 table spoons of onion powder ;

2 table spoons = 1 servings

10 table spoons = x servings

we cross multiply;

x servings × 2 table spoons = 10 table spoons × 1 servings

x servings = ( 10 table spoons × 1 servings ) / 2 table spoons

x = 10 / 2

x = 5 servings

Therefore, we can make 5 servings of spice rub from 10 table spoons of onion powder

3 0

3 years ago

Here are the endpoints of the segments BC, FG, and JK.<br> B, −67

yulyashka [42]

$~~~~~~~~~~~~\textit{distance between 2 points} \\\\ B(\stackrel{x_1}{-6}~,~\stackrel{y_1}{7})\qquad C(\stackrel{x_2}{-4}~,~\stackrel{y_2}{4})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ BC=\sqrt{[-4 - (-6)]^2 + [4 - 7]^2}\implies BC=\sqrt{(-4+6)^2+(-3)^2} \\\\\\ BC=\sqrt{2^2+(-3)^2}\implies \boxed{BC=\sqrt{13}} \\\\[-0.35em] ~\dotfill\\\\ ~~~~~~~~~~~~\textit{distance between 2 points}$

$F(\stackrel{x_1}{-2}~,~\stackrel{y_1}{-4})\qquad G(\stackrel{x_2}{1}~,~\stackrel{y_2}{-2})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ FG=\sqrt{[1 - (-2)]^2 + [-2 - (-4)]^2}\implies FG=\sqrt{(1+2)^2+(-2+4)^2} \\\\\\ FG=\sqrt{9+4}\implies \boxed{FG=\sqrt{13}} \\\\[-0.35em] ~\dotfill\\\\ ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ J(\stackrel{x_1}{4}~,~\stackrel{y_1}{2})\qquad K(\stackrel{x_2}{5}~,~\stackrel{y_2}{-2})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}$

$JK=\sqrt{[5 - 4]^2 + [-2 - 2]^2}\implies JK=\sqrt{1^2+(-4)^2}\implies \boxed{JK=\sqrt{17}} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \overline{BC}\cong \overline{FG}~\hfill$