Question

I need help with this promblem it’s ALGEBRA 2!

Answer 1

Answer:

$(f\circ h)(2)=2$

Step-by-step explanation:

Composite Function

Given f(x) and h(x) real functions, the composite function named $(f\circ h)(x)$ is defined as:

$(f\circ h)(x)=f(h(x))$

It can be found by substituting h into f.

We are given the functions:

$f(x)=2x^2-9x+2$

$h(x)=x^2-4$

It's required to find $(f\circ h)(2)$

As defined above:

$(f\circ h)(x)=f(h(x))$

Thus:

$(f\circ h)(2)=f(h(2))$

Find h(2):

$h(2)=2^2-4=0$

h(2)=0

Now:

$(f\circ h)(2)=2(0)^2-9(0)+2$

$(f\circ h)(2)=2$