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3 years ago

Please help me guys 20 points How do you do e

Mathematics

2 answers:

sineoko [7]3 years ago

6 0

You add them all up

miv72 [106K]3 years ago

6 0

The answer is
x≈ 0.38024567

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Look at the figure below:

kati45 [8]

Answer:

Angle 50 and common side, in triangle MNT the sum of angles m and t is 130. In triangle PMN the sum of angles n, m is 130

Step-by-step explanation:

4 0

3 years ago

What will be the linear equation for the shown table?<br><br>

vladimir1956 [14]

Answer:

y=2x+5

Step-by-step explanation:

To find a linear equation you must find the slope and y intercept to create an equation in y=mx+b form (slope-intercept form)

So slope is = y2-y1 / x2-x1 [2 and 1 are subscripts] so 11-7/3-1 so m=4/2 = 2

Slope = 2, now find b

So using y = mx + b, substitute what you know so 7 = 2(1) + b so b=7-2 = 5

Put it all together y = 2x + 5

3 0

3 years ago

1. The area of a circle is 60 square units. What is the area of ...

AVprozaik [17]

Multiply the area of the circle by the percentage:

60 square units x 50% = 60 x 0.50 = 30

50% 0f the circle id 30 square units.

3 0

2 years ago

A ferry will safely accommodate 82 tons of passenger cars. Assume that the meanweight of a passenger car is 2 tons with standard

Shalnov [3]

Answer:

The probability that the maximum safe-weight will be exceeded is <u>0.0455 or 4.55%</u>.

Step-by-step explanation:

Given:

Maximum safe-weight of 37 cars = 82 tons

∴ Maximum safe-weight of 1 car (x) = 82 ÷ 37 = 2.22 tons (Unitary method)

Mean weight of 1 car (μ) = 2 tons

Standard deviation of 37 cars = 0.8 tons

So, standard deviation of 1 car is given as:

$\sigma=\frac{0.8}{\sqrt{37}}=0.13$

Probability that maximum safe-weight is exceeded, P(x > 2.22) = ?

The sample is normally distributed (Assume)

Now, let us determine the z-score of the mean weight.

The z-score is given as:

$z=\frac{x-\mu}{\sigma}\\\\z=\frac{2.22-2}{0.13}\\\\z=\frac{0.22}{0.13}=1.69$

Now, finding P(x > 2.22) is same as finding P(z > 1.69).

From the z-score table of normal distribution curve, the value of area under the curve for z < 1.69 is 0.9545.

But we need the area under the curve for z > 1.69.

So, we subtract from the total area. Total area is 1 or 100%.

So, $P(z > 1.69) = 1 - P(z < 1.69)$

$P(z>1.69)=1-0.9545=0.0455\ or\ 4.55\%$

Therefore, the probability that the maximum safe-weight will be exceeded is 0.0455 or 4.55%.

8 0

4 years ago

True or false by definition a simple random sample of size n

Sophie [7]

True

I hope I helped you out

7 0

4 years ago