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2 years ago

Which of these is the absolute value parent function?

Mathematics

1 answer:

jenyasd209 [6]2 years ago

8 0

I think the correct answer is b

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How to solve this one step inequality

dem82 [27]

Answer: add 1 to both sides

-1+r+1≥4+1

simplify

x≥5

Step-by-step explanation:

8 0

3 years ago

What is the factored form of 8x^2+12x

Anestetic [448]

Answer:

4x(2x+3)

Step-by-step explanation:

Since the common factor of 8x^2 and 12x is 4x, put that out and separate the distributed remaining factors.

6 0

3 years ago

Solve for x in the following equation. X/5=25 X=?

worty [1.4K]

Answer:

125

Step-by-step explanation:

25 × 5 = 125

x/5 = 25 × 5 = 125

x = 125

4 0

2 years ago

Read 2 more answers

Factorise the following 5y^2-20y-8z+2yz

andre [41]

Answer:

$(5y+2z)(y-4)$

Step-by-step explanation:

$5y^2-20y-8z+2yz=\\5y^2-20y+2yz-8z=\\5y(y-4)+2z(y-4)=\\(5y+2z)(y-4)$

8 0

2 years ago

Find the indicated limit, if it exists.

kondor19780726 [428]

Answer:

d) The limit does not exist

General Formulas and Concepts:

Calculus

Limits

Right-Side Limit: $\displaystyle \lim_{x \to c^+} f(x)$
Left-Side Limit: $\displaystyle \lim_{x \to c^-} f(x)$

Limit Rule [Variable Direct Substitution]: $\displaystyle \lim_{x \to c} x = c$

Limit Property [Addition/Subtraction]: $\displaystyle \lim_{x \to c} [f(x) \pm g(x)] = \lim_{x \to c} f(x) \pm \lim_{x \to c} g(x)$

Step-by-step explanation:

*Note:

In order for a limit to exist, the right-side and left-side limits must equal each other.

Step 1: Define

Identify

$\displaystyle f(x) = \left\{\begin{array}{ccc}5 - x,\ x < 5\\8,\ x = 5\\x + 3,\ x > 5\end{array}$

Step 2: Find Right-Side Limit

Substitute in function [Limit]: $\displaystyle \lim_{x \to 5^+} 5 - x$
Evaluate limit [Limit Rule - Variable Direct Substitution]: $\displaystyle \lim_{x \to 5^+} 5 - x = 5 - 5 = 0$

Step 3: Find Left-Side Limit

Substitute in function [Limit]: $\displaystyle \lim_{x \to 5^-} x + 3$
Evaluate limit [Limit Rule - Variable Direct Substitution]: $\displaystyle \lim_{x \to 5^+} x + 3 = 5 + 3 = 8$

∴ Since $\displaystyle \lim_{x \to 5^+} f(x) \neq \lim_{x \to 5^-} f(x)$ , then $\displaystyle \lim_{x \to 5} f(x) = DNE$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Limits

5 0

2 years ago