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aev [14]
3 years ago
6

Plz help i dont understand anything

Mathematics
1 answer:
scoundrel [369]3 years ago
5 0

Answer:

A= B and B= C

Step-by-step explanation:

I hope it helps. (Sorry if it doesn't)

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Is o a integer but not a whole number
podryga [215]
Zero is actually a whole number, rational number, and integer, but it is not a natural number
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3 years ago
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Perform the operation. (-2x^2-4x+2)-(-6x+2) (−2x 2 −4x+2)−(−6x+2)
AleksandrR [38]

Answer:

-50x^2+30x-4

Step-by-step explanation:

4 0
3 years ago
For questions 3 – 5, an airplane is heading south at an airspeed of 540 km/hr, but there is a wind blowing from the northeast at
GuDViN [60]

First, let's calculate the horizontal and vertical components of the wind speed (W) and the airplane speed (A), knowing that south is a bearing of 270° and northeast is a bearing of 45°:

\begin{gathered} W_x=W\cos45°\\ \\ W_x=50\cdot0.707\\ \\ W_x=35.35\\ \\ \\ \\ W_y=W\sin45°\\ \\ W_y=50\cdot0.707\\ \\ W_y=35.35 \end{gathered}\begin{gathered} A_x=A\cos270°\\ \\ A_x=540\cdot0\\ \\ A_x=0\\ \\ \\ \\ A_y=A\sin270°\\ \\ A_y=540\cdot(-1)\\ \\ A_y=-540 \end{gathered}

Now, let's add the components of the same direction:

\begin{gathered} V_x=W_x+A_x=35.35+0=35.35\\ \\ V_y=W_y+A_y=35.35-540=-504.65 \end{gathered}

To find the resultant bearing (theta), we can use the formula below:

\begin{gathered} \theta=\tan^{-1}(\frac{V_y}{V_x})\\ \\ \theta=\tan^{-1}(\frac{-504.65}{35.35})\\ \\ \theta=-86° \end{gathered}

The angle -86° is equivalent to -86 + 360 = 274°.

Therefore the correct option is b.

8 0
1 year ago
Is my answer correct
Kryger [21]
Yes it is thirty because when u do 5×2×3 the correct answer turns out to be 30 $o yes!!!!!!
4 0
3 years ago
Read 2 more answers
Help me please explain do not need work just explain THANK YOU I NEED HELP
Mnenie [13.5K]
Alright, 

you will need to solve for each variable to find if they got the equation correctly or not.. 

Let's start with h 
isolate h 
(1/2)h = A/(b1+b2)
Now we need to get rid of 1/2 we may do so by multiplying both sides by 2 

h = 2(A/(b1+b2))

And that's not how they did it for h so Option D doesn't apply 


Let's see C
Also doesn't apply since they multiplied 2 only by A rather than A/h

Let's see B
Also not correct they made the same mistake as with option C

Let's see A
again same mistake 
when multiplying both sides by 2 
the 2 should be as following 
2\frac{A}{h}

I believe you should contact your instructor and explain that non of the options is right. 

6 0
3 years ago
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