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Stels [109]
3 years ago
7

Martin is paid an hourly rate of d dollars per hour for the first 40 he works per week. for each hour he works in excess of 40 p

er week Martin was paid 770 for working 50 hours in one week, which equation can be
Mathematics
1 answer:
Andre45 [30]3 years ago
5 0
Do you have the rest of the question?
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A survey indicated that 3 out of 5 doctors use brand x aspirin. If 2000 doctors were surveyed how many used brand x? show work p
Katena32 [7]
Divide 2000 by 5 and then multiply by 3 to get your answer. 
2000/5=400 
400x3=1200 

so 1200 doctors used brand x. ;) 
3 0
3 years ago
Read 2 more answers
Can someone fill in the blank<br> I can’t figure it out
stealth61 [152]

Answer:

I THINK THIS IS THE ANSWER... NOT 100% SURE: subtraction; division; division; multiplication (left to right)

Step-by-step explanation:

7-(15/5) /(2x1)=2

7-(3)/(2)=2

4/2=2

2=2

3 0
3 years ago
Help with geometry homework?<br><br> Answer choices:<br><br> a 2<br> b 5<br> c 17<br> d 32
Vlad1618 [11]
It already tells you that AE = AC and BE = BD.
so it just have to be AD = BC.
5y+7=7y-3 and y is 5.
8 0
3 years ago
Let X be a Binomial Random Variable with 8 trials and a probability of success as 0.37. Suppose you want to find k such that P(X
larisa86 [58]

Answer:

k = 4

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

n = 8, p = 0.37. So

P(X < k) = 0.6625

k only assumes discrete values, so

P(X < k) = P(X \leq k-1) = 0.6625

We have to find the cummulative distribution until we hit 0.6625. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{8,0}.(0.37)^{0}.(0.63)^{8} = 0.0248

P(X \leq 0) = P(X = 0) = 0.0248

P(X = 1) = C_{8,1}.(0.37)^{1}.(0.63)^{7} = 0.1166

P(X \leq 1) = P(X = 0) + P(X = 1) = 0.0248 + 0.1166 = 0.1414

P(X = 2) = C_{8,2}.(0.37)^{2}.(0.63)^{6} = 0.2397

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0248 + 0.1166 + 0.2397 = 0.3811

P(X = 3) = C_{8,3}.(0.37)^{3}.(0.63)^{5} = 0.2814

P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.0248 + 0.1166 + 0.2397 + 0.2814 = 0.6625

P(X \leq 3) = P(X < 4) = 0.665

So k = 4

7 0
3 years ago
Suppose you could choose 2 boxes of markers. Find all the possible pairs. 15 markers 24 markers 36 markers 48 markers. Find all
Vladimir79 [104]
15 & 24
15 & 36
15 & 48
24 & 36
24 & 48
36 & 48
are the answers,
need help tag me :D
7 0
3 years ago
Read 2 more answers
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