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lukranit [14]
3 years ago
7

Please help me with 19

Mathematics
2 answers:
MaRussiya [10]3 years ago
8 0
I got 2/5ths as my answer
andrew-mc [135]3 years ago
7 0
The answer to 19th 2/3
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−3t≥39 What is the answer
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-3t ≥39

-3t/-3 ≥39/-3

t≤-13

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2 years ago
Express sin Q as a fraction in simplest terms.​
Lesechka [4]

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Solution given

Sin Q=opposite/hypotenuse=28/29

<u>28/29</u><u> </u><u>is</u><u>. </u><u>a</u><u> </u><u>required</u><u> </u><u>answer</u><u>.</u><u />

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The Petri dish shown has no lid. What is the surface area of the outside of the Petri dish?
Nata [24]

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Step-by-step explanation:

3 0
3 years ago
A student says the prime factors of 17 are 1 and 17. is the student correct?​
Ksivusya [100]

Answer: yes

A prime factor is number that can only divided by itself and one

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Step-by-step explanation:

7 0
2 years ago
A solid oblique pyramid has a regular hexagon base with an area of 54_/3 cm^2 and an edge length of 6cm. Angle BAC measures 60 d
Lady_Fox [76]

Answer: The answer is (C) 324 cubic cm.


Step-by-step explanation: As given in the question, given a solid oblique pyramid with a regular hexagonal base and area 54√3 cm². Also, the edge length of the base is 6cm and ∠BAC = 60°.

We are to find the volume of the pyramid.

The formula for finding the volume of a pyramid is given by

V=\dfrac{1}{3}b\times h,

where, 'b' is the base area and 'h' is the perpendicular height of the pyramid.

Here, b = 54√3 cm², h = ?

Now, from the right-angled triangle ABC, we have

\dfrac{\textup{BC}}{\textup{AC}}=\tan 60^\circ\\\\\Rightarrow \dfrac{h}{6}=\sqrt 3\\\\\Rightarrow h=6\sqrt 3.

Therefore, the volume of the pyramid is

V=\dfrac{1}{3}b\times h=\dfrac{1}{3}\times 54\sqrt 3\times 6\sqrt 3=324.

Thus, the required volume is V=324~\textup{cm}^3. This makes (C) as the correct option.



5 0
3 years ago
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