<span>Binomial Problem with n = 50 and P(op) = 0.0.7
P(31<=50) = 1 - P(0<=x<=30) = 1 - binomcdf(50,0.7,30) = 1-0.0848 = 0.9152
</span>
To factor quadratic equations of the form ax^2+bx+c=y, you must find two values, j and k, which satisfy two conditions.
jk=ac and j+k=b
The you replace the single linear term bx with jx and kx. Finally then you factor the first pair of terms and the second pair of terms. In this problem...
2k^2-5k-18=0
2k^2+4k-9k-18=0
2k(k+2)-9(k+2)=0
(2k-9)(k+2)=0
so k=-2 and 9/2
k=(-2, 4.5)
Answer:
Option D.
Step-by-step explanation:
Consider option D. 
Take point (0,0)
On putting this point in inequation 
, we get
which is true . So, solution is region towards the origin i,e region below the line 
including the line itself .
On putting (0,0) in inequation 
, we get 
which is false , so solution is region away from the origin i.e region below line 
including the line itself .
So, common solution to both the inequations is the shaded part in the given figure .
In other words, we can say that the graph shown in the given figure represents system of equations:
Answer:
Step-by-step explanation:
probability ∈[0,1]
or probability ≥0
and ≤1
so a,b,g cannot be the probability of an event.
Answer: I think the answer is D
Step-by-step explanation:
