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AlekseyPX
2 years ago
8

The sum of four and twice a number is 56. Find the number.​

Mathematics
2 answers:
kotegsom [21]2 years ago
5 0

Answer:

26

Step-by-step explanation:

4 + 2x = 56

2x = 56 - 4

x = 52/2

x = 26

kari74 [83]2 years ago
5 0

Answer:

26

Step-by-step explanation:

Let the missing number be x.

Given that,

→ Sum of four and twice a number is 56.

Let's form a equation,

→ 4 + 2x = 56

The required value of x will be,

→ 4 + 2x = 56

→ 2x = 56 - 4

→ 2x = 52

→ x = 52/2

→ [ x = 26 ]

Hence, the number is 26.

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If DA = 6 and MD = 4, what is the length of DK?
Leto [7]

Answer:

DK = 9

Step-by-step explanation:

In triangle AMD,

h² = p² + b²

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or, h²= 36 + 16

so, h² = 52

so, AM² = 52

Take x as reference angle,

cos²x = 16/52

Now,

In triangle, AMK,

Taking x as reference angle,

cos²x = b²/h²

cos²x = AM²/MK²

or, cos²x = 52/MK²

Now,

cos²x = 16/52 = 52/MK²

or,

16/52 = 52/MK²

or, 16MK² = 2704

or, MK² = 2704/16

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Now,

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3 0
2 years ago
The percent of concentration of a certain drug in the bloodstream x hours after the drug is administered is given by K(x) 5x/x^2
Olegator [25]

Given :

The percent of concentration of a certain drug in the bloodstream x hours after the drug is administered is given by K(x) = \dfrac{5x}{x^2+9}.

To Find :

Find the time at which the concentration is a maximum. b. Find the maximum concentration.

Solution :

For maximum value of x, K'(x) = 0.

K'(x) = \dfrac{5(x^2+9)- 5x(2x)}{(x^2+9)^2}=0\\\\5x^2+45-10x^2=0\\\\5x^2 = 45\\\\x = \pm 3

Since, time cannot be negative, so ignoring x = -3 .

Putting value of x = 3, we get, K(3) = 15/( 9 + 9) = 5/6

Therefore, maximum value drug in bloodstream is 5/6 at time x = 3 units.

Hence, this is the required solution.

5 0
3 years ago
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