A boy walks 6 km from a point P to a point Q on a bearing of 065. He then walks to a point R at a distance of 13 km on a bearing of 146. (1) sketch the diagram of his movements (2) calculate correct to the nearest kilometre, the distance PR
1 answer:
9514 1404 393
Answer:
see below for a sketch 12 km Step-by-step explanation:
The distance can be calculated using the Law of Cosines. The angle internal to the triangle at Q is (180°-(146° -65°)) = 99°. Then the distance PR can be found from ...
PR² = PQ² +QR² -2·PQ·QR·cos(∠PQR)
PR² = 6² +10² -2·6·10·cos(99°) ≈ 154.77
PR ≈ √154.77 ≈ 12.44 . . . . km
The distance PR is about 12 km .
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2184 You have to simplify the first equation until you get x= something. The fill that in the x spot in the second equation.
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X² = 5 take root to both side to clear the square √x² = ±√5 X = ±√5
Here is the work with the answer. Hope this helps. God bless